Coulomb pressure and concentric spheres

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SUMMARY

The discussion centers on the interaction between a positively charged sphere of radius 'a' and a concentric negatively charged shell extending from 'a' to 'b'. The participants debate whether there is an outward pressure at radius 'a' calculated as kqq/a²/(4πa²), which decreases with radius and becomes zero at 'b', or if there is an attraction resulting in zero pressure everywhere. The problem is likened to a hydrostatics scenario, leading to the equation ∇p(r) = -ρE(r) and the equivalent ∇(p - ρφ) = 0 for field strength analysis.

PREREQUISITES
  • Understanding of electrostatics and Coulomb's law
  • Familiarity with concepts of electric field strength and pressure
  • Knowledge of hydrostatics principles
  • Basic calculus for understanding gradient operations
NEXT STEPS
  • Study the derivation of electric field strength for concentric charged spheres
  • Explore hydrostatic pressure equations in electrostatic contexts
  • Investigate the implications of charge distribution on pressure and field strength
  • Learn about the mathematical treatment of gradients in electrostatics
USEFUL FOR

This discussion is beneficial for physicists, electrical engineers, and students studying electrostatics and fluid mechanics, particularly those interested in the interactions of charged bodies and pressure dynamics.

MarkL
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Suppose you have a sphere of radius a of positive charge, and a concentric shell from a to b of negative charge. The positive charge is equal to the negative charge. (non-conducting, uniform density)
Is there an outward pressure at a of kqq/a2/(4πa2) - with pressure decreasing with radius, becoming P = 0 at b.
Or, is there an attraction between the sphere and the shell --> P = 0 everywhere. The thickness of the shell does not matter. What if b was infinity?
Thanks
 
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Do you know how to solve the problem for the field strength? Because it's the same as a hydrostatics problem with ##\nabla p(r) = -\rho \mathbf{E}(r)##. Equivalently ##\nabla(p - \rho \phi) = 0##.
 

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