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Coulombs force law in a three dimensional coordinate system problem

  1. Jul 25, 2013 #1
    Two point charges of Q1 = +37 nC and Q2 = +70 nC are located at points (1,3,0) m and (0,0,2) m, respectively.

    Q : Calculate the force exerted on Q2 by Q1.

    Attempt : I applied phythagoras theorem to find the distance between Q1 and Q2, I then applied coulombs force law equation directly given r,Q1,Q2, however im puzzled to how I could find the direction of the force and how possible i could solve the problem in vector notation ..
     
  2. jcsd
  3. Jul 25, 2013 #2

    ehild

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    Hi SirPlus, welcome to PF.

    What does Coulomb's law say about the direction of the force between two charges?

    ehild
     
  4. Jul 25, 2013 #3
    Nothing much, it simply tells us about the magnitude of the electrostatic force exerted on charge by the other and that this force is directly proportional to the product of charges and inversly proportional to the square of the distance between the centre of the charges - i am however intersted in the orientation of the coulombs force in a 3d space like a coordinate system, after all force is a vector quantity...
     
  5. Jul 25, 2013 #4
    Thanks for the invitation dude
     
  6. Jul 25, 2013 #5

    vanhees71

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    That's right! Forces are vectors. For the Coulomb Law it's
    [tex]\vec{F}=\frac{q_1 q_2 (\vec{r}_1-\vec{r}_2)}{|\vec{r}_1-\vec{r}_2|^3}.[/tex]
    That's the force acting on a charge [itex]q_1[/itex] at position [itex]\vec{r}_1[/itex] due to a charge [itex]q_2[/itex] at position [itex]\vec{r}_2[/itex] (in Heaviside-Lorentz units).
     
  7. Jul 25, 2013 #6

    ehild

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    See: http://faculty.wwu.edu/vawter/PhysicsNet/Topics/ElectricForce/CoulombLaw.html [Broken]

    The Coulomb force is a vector, parallel with the line connecting the charges. The force q1 exerts on q2 points from q1 to q2, parallel with the difference of the position vectors Δr=r2-r1, if both charges have the same sign, otherwise it is in the opposite direction.
    The exact, vectorial formula of the Coulomb force is what vanhees71 wrote. You need to multiply the magnitude of the Coulomb force with the unit vector parallel to Δr.

    ehild
     
    Last edited by a moderator: May 6, 2017
  8. Jul 25, 2013 #7
    Sure, but doesn't tell me anything about the orientation of the force in a three dimensional space?
     
  9. Jul 25, 2013 #8

    ehild

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    It does. The force is parallel to the difference of the position vectors. The position vectors r1 and r2 are given. What is their difference?

    ehild
     
  10. Jul 25, 2013 #9
    Thanks so we use vector notation, thanks pretty clear now ...
     
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