Coulomb's Law Can someone I don't understand how to do this.

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    Coulomb's law Law
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SUMMARY

This discussion centers on applying Coulomb's Law to determine the necessary movements of charged particles to manipulate the net electric force on a fixed charge. The problem involves calculating the forces acting on particle 5, which is fixed at the origin, due to particles 1 and 3, both of charge -e, and particles 2 and 4, both of charge -e, fixed on the y-axis. The user is advised to utilize the principle of superposition to compute the net electric force direction and magnitude acting on particle 5, starting from the initial positions of particles 1 and 3.

PREREQUISITES
  • Coulomb's Law (FE = k(Qe*qp)/r²)
  • Principle of Superposition in electrostatics
  • Vector addition of forces
  • Understanding of electric charge interactions
NEXT STEPS
  • Calculate net electric force on particle 5 using initial positions of particles 1 and 3.
  • Determine the new x position for particle 1 to achieve a 30.1° counterclockwise rotation of the net force.
  • Calculate the required x position for particle 3 to revert the net force back to its original direction.
  • Explore vector components of forces to understand their contributions in both x and y directions.
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Students studying electrostatics, physics educators, and anyone seeking to understand the application of Coulomb's Law in multi-charge systems.

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Homework Statement



In the figure 21-29, particles 2 and 4, of charge -e, are fixed in place on a y axis, at y2 = -7.20 cm and y4 = 16.6 cm. Particles 1 and 3, of charge -e, can be moved along the x axis. Particle 5, of charge +e, is fixed at the origin. Initially particle 1 is at x1 = -9.84 cm and particle 3 is at x3 = 9.84 cm. (a) To what x value must particle 1 be moved to rotate the direction of the net electric force net on particle 5 by 30.1o counterclockwise? (b) With particle 1 fixed at its new position, to what x value must you move particle 3 to rotate net back to its original position?

......|......
......|......
......4......
......|......
......|......
-------1------5-------3------
......|......
......|......
......2......
......|......


I tried to represent the picture that was provided as accurate as possible.
here is the actual picture that I was provided with.
http://edugen.wiley.com/edugen/courses/crs1650/art/qb/qu/c21/fig21_38.gif



Homework Equations


Ok I know that I am supposed to use
FE = k(Qe*qp)/r2)
I can get the force that each one has on point 5 just by using the equation above but then I am stuck.


The Attempt at a Solution


I have not attempted the solution yet because I don't know where to start.
 
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Okay. I assume you have heard about the principle of superposition, i.e., that you can add up (vectorially) the force due to each of the charges on anyone given charge. Using this principle (and Coulomb's Law), first compute the direction of the net electric force on particle 5 when particle 1 is at its initial position. Note that force is a vector: so you will have to specify the direction of the net force (as well as its magnitude) when you state the answer. Once you have done this, more help will follow!
 
IPart said:
Okay. I assume you have heard about the principle of superposition, i.e., that you can add up (vectorially) the force due to each of the charges on anyone given charge. Using this principle (and Coulomb's Law), first compute the direction of the net electric force on particle 5 when particle 1 is at its initial position. Note that force is a vector: so you will have to specify the direction of the net force (as well as its magnitude) when you state the answer. Once you have done this, more help will follow!

Ok Since Fx net = 0 the only ones to take into account are the y directions.
I have come up with Fnet = -F52 + F54 = |3.622*10-26|

And the direction is towards the -y correct?
Or am I completely off base?
 
Last edited:

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