What Is the Mass of the Second Particle and the Magnitude of the Charges?

  • Thread starter Thread starter Saladsamurai
  • Start date Start date
  • Tags Tags
    Coulomb's law Law
Click For Summary
SUMMARY

The discussion centers on calculating the mass of a second particle and the magnitude of charges for two equally charged particles separated by 3.2 x 10-3 m, with known accelerations of 7 m/s2 and 9 m/s2. The mass of the first particle is given as m1 = 6.3 x 10-7 kg. The relationship between the forces acting on the particles is established using Newton's second law (F = ma) and the electrostatic force equation (F = kq1q2/r2), confirming that the forces are equal due to Newton's third law.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with electrostatic force equations
  • Basic knowledge of particle dynamics
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Calculate the mass of the second particle using m1a1 = m2a2
  • Determine the magnitude of the charges using F = kq1q2/r2
  • Review Newton's third law and its implications in particle interactions
  • Explore the concept of action-reaction pairs in physics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and electrostatics, as well as educators seeking to clarify concepts related to forces and particle interactions.

Saladsamurai
Messages
3,009
Reaction score
7

Homework Statement


Two equally charged particles are held 3.2*10^(-3)m apart and released from rest. The initial acceleration of the first is 7 m/s^2 and that of the second is 9 m/s^2.

If the mass of the first is m1= 6.3*10^(-7) kg, what are a) the mass of the second particle and b) the magnitude of the charge of each?



Homework Equations



F=ma
F=kq1q2/r^2


The Attempt at a Solution



I just need a kick in the right direction here. I am looking at a worked solution to the first part and they make the assumption

F1=F2 , thus, m1a1=m2a2

But, for some reason I am uneasy with this. Why are these two forces equal?

Sorry for the lame question... I am out of practice and am trying to do some review.

Thanks
 
Physics news on Phys.org
Saladsamurai said:

Homework Statement


Two equally charged particles are held 3.2*10^(-3)m apart and released from rest. The initial acceleration of the first is 7 m/s^2 and that of the second is 9 m/s^2.

If the mass of the first is m1= 6.3*10^(-7) kg, what are a) the mass of the second particle and b) the magnitude of the charge of each?



Homework Equations



F=ma
F=kq1q2/r^2


The Attempt at a Solution



I just need a kick in the right direction here. I am looking at a worked solution to the first part and they make the assumption

F1=F2 , thus, m1a1=m2a2

But, for some reason I am uneasy with this. Why are these two forces equal?

Sorry for the lame question... I am out of practice and am trying to do some review.

Thanks
They form an action-reaction pair (Newton's third law). They must be equal!
 
F = q1q2 /r^2

q1q2 is the same for both particles, as is r.
 
nrqed said:
They form an action-reaction pair (Newton's third law). They must be equal!

I guess I can live with that.
 

Similar threads

Replies
18
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 6 ·
Replies
6
Views
10K
Replies
6
Views
8K
Replies
5
Views
7K