1. The problem statement, all variables and given/known data An electric motor draws 20.0 A of current when first switched on. The motors windings have a resistance of 5.0 ohm. Once the motor is up to full speed it draws only 4.4 A of current. Calculate the counter emf generated in the motor at full speed 2. Relevant equations I = V/R V=IR 3. The attempt at a solution R = 5.0 ohm A1 = 20.0 A A2= 4.4 A n 1. (20A)(5.0ohm) = 100 V 2. (4.4A)(5.0ohm) = 22V 3. 100V - 22V = 78V Im told im missing some "change", however I think this is correct, it is change in voltage?