Countour Integ & Fourier Transform (1 Viewer)

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Why is it that we don't use contour integration when we take the integral of a complex function to find the fourier transform:

[tex]X(j\omega) = \int_{-\infty}^\infty x(t) e^{- j\omega t} dt [/tex]
 

HallsofIvy

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Here, t is obviously a real number, not a complex number. You can use contour integration- there are a number of techniques for using contour integration to find a real integral- you include the portion of the real line you are integrating on in the contour- but the integral you show is NOT itself a contour integral.
 
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Oh, I see. Thanks!
 

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