1. Feb 20, 2007 #1

   Swapnil

   

   Why is it that we don't use contour integration when we take the integral of a complex function to find the fourier transform:
   
   [tex]X(j\omega) = \int_{-\infty}^\infty x(t) e^{- j\omega t} dt [/tex]

    

   Swapnil, Feb 20, 2007
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3. Feb 21, 2007 #2

   HallsofIvy

   

   Staff Emeritus

   Science Advisor

   Here, t is obviously a real number, not a complex number. You can use contour integration- there are a number of techniques for using contour integration to find a real integral- you include the portion of the real line you are integrating on in the contour- but the integral you show is NOT itself a contour integral.

    

   HallsofIvy, Feb 21, 2007
4. Feb 21, 2007 #3

   Swapnil

   

   Oh, I see. Thanks!

    

   Swapnil, Feb 21, 2007

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