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Countour Integ & Fourier Transform

  1. Feb 20, 2007 #1
    Why is it that we don't use contour integration when we take the integral of a complex function to find the fourier transform:

    [tex]X(j\omega) = \int_{-\infty}^\infty x(t) e^{- j\omega t} dt [/tex]
     
  2. jcsd
  3. Feb 21, 2007 #2

    HallsofIvy

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    Here, t is obviously a real number, not a complex number. You can use contour integration- there are a number of techniques for using contour integration to find a real integral- you include the portion of the real line you are integrating on in the contour- but the integral you show is NOT itself a contour integral.
     
  4. Feb 21, 2007 #3
    Oh, I see. Thanks!
     
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