1. Feb 20, 2007 #1

   Swapnil

   

   Why is it that we don't use contour integration when we take the integral of a complex function to find the fourier transform:
   
   [tex]X(j\omega) = \int_{-\infty}^\infty x(t) e^{- j\omega t} dt [/tex]

    

   Swapnil, Feb 20, 2007
2. 
   Phys.org - latest science and technology news stories on Phys.org

   • • The math of doughnuts: 'Moonshine' sheds light on elliptic curves
   • • Five ways ancient India changed the world – with maths
   • • Nothing matters: how the invention of zero helped create modern mathematics
3. Feb 21, 2007 #2

   HallsofIvy

   

   Staff Emeritus

   Science Advisor

   Here, t is obviously a real number, not a complex number. You can use contour integration- there are a number of techniques for using contour integration to find a real integral- you include the portion of the real line you are integrating on in the contour- but the integral you show is NOT itself a contour integral.

    

   HallsofIvy, Feb 21, 2007
4. Feb 21, 2007 #3

   Swapnil

   

   Oh, I see. Thanks!

    

   Swapnil, Feb 21, 2007

• Log in with Facebook
• Log in with Twitter

Your name or email address:

Do you already have an account?

• No, create an account now.
• Yes, my password is:
• Forgot your password?

Stay logged in