Coupled oscillators -- period of normal modes

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Homework Help Overview

The discussion revolves around coupled oscillators, specifically focusing on the normal modes of a system with two masses. The original poster presents equations derived from Newton's laws to describe the motion of the masses and identifies two normal modes: the pendulum mode and the breathing mode. There is uncertainty regarding the period of the breathing mode due to missing parameters.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the derivation of normal modes and their corresponding frequencies. There are inquiries about the physical arrangement of the system and the significance of a given period related to one of the masses. Some participants question how to relate the known period to the normal modes.

Discussion Status

Participants are actively exploring the relationship between the period of one mass and the parameters of the normal modes. Some guidance has been offered regarding the interpretation of the period, but there is still a lack of consensus on how to correctly apply this information to find the period for the breathing mode.

Contextual Notes

There is a mention of needing a diagram or description of the physical setup, which may affect the understanding of the problem. Additionally, the discussion reflects uncertainty about the values of certain parameters, such as k and m, which are crucial for solving the problem.

happyparticle
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Homework Statement
I have to determine the periods of the normal modes.

I have 2 mass ##m_1 = m_2##, l = 1.2m and if I hold vertically one of the mass the period of the other mass is 1.5s.
Relevant Equations
F = ma

##m\ddot x = -\frac{mgx_1}{l} -k(x_1 - x_2)##
##m\ddot x_2 = -\frac{mgx_2}{l} +k(x_1 - x_2)##
Hi,

I know there's are 2 normal modes because the system has 2 mass. I did the Newton's law for both mass.

##m\ddot x_1 = -\frac{mgx_1}{l} -k(x_1 - x_2)## (1)
##m\ddot x_2 = -\frac{mgx_2}{l} +k(x_1 - x_2)## (2)

In the pendulum mode ##x_1 = x_2## and in the breathing mode ##x_1 = -x_2##

I get the pendulum and breathing mode by adding equation 1 and 2 and subtracting 1 and 2 then I replace ##x_1-x_2## by q2 and ##x_1+x_2## by q1.
Finally I have ##\omega_p = \sqrt{\frac{g}{l}}## and ##\omega_b = \sqrt{\frac{g}{l} + \frac{2k}{m}}##
It's quite easy to get the period for ##\omega_p##. However, I'm not sure how to find the period for ##\omega_b##, since I don't have k and m.

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You will need to supply a diagram or a full description of the physical arrangement. In particular, I am confused regarding whether these x displacements are horizontal or vertical.
 
haruspex said:
You will need to supply a diagram or a full description of the physical arrangement. In particular, I am confused regarding whether these x displacements are horizontal or vertical.
My bad, sorry. I uploaded an image.
 
EpselonZero said:
My bad, sorry. I uploaded an image.
Doesn't this tell you k/m?
"if I hold vertically one of the mass the period of the other mass is 1.5s."
 
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haruspex said:
Doesn't this tell you k/m?
"if I hold vertically one of the mass the period of the other mass is 1.5s."

I need to find the period for the normal modes. I don't see the link between 1.5s and the normal modes.
 
EpselonZero said:
I need to find the period for the normal modes. I don't see the link between 1.5s and the normal modes.
You wrote that what was blocking you was that you did not know k/m.
What wouid the period be if you suspended one of the masses from the other and let it oscillate vertically?
 
I see...

Can I plug ##\frac{1.5}{2\pi}## to find ##\omega_b##?

It seems too easy.
 
EpselonZero said:
I see...

Can I plug ##\frac{1.5}{2\pi}## to find ##\omega_b##?

It seems too easy.
not quite that simple... it tells you k/m. Your equation for ##\omega_b## has another term
 
##\omega_b = \sqrt{\frac{g}{l} + \frac{2k}{m}}##
##g = 9.8## and ##l = 1.2##

##\omega_b = \sqrt{8.2 + 2(\frac{1.5}{2pi})}##

Is it correct?
 
  • #10
EpselonZero said:
##\omega_b = \sqrt{\frac{g}{l} + \frac{2k}{m}}##
##g = 9.8## and ##l = 1.2##

##\omega_b = \sqrt{8.2 + 2(\frac{1.5}{2pi})}##

Is it correct?
Doesn’t look right to me.
What is the expression for the period of a mass on a spring?
 
  • #11
Right, I made a mistake.

##\omega_b = \sqrt{8.2 +2(\frac{2\pi}{1.5})^2}##
 
  • #12
EpselonZero said:
Right, I made a mistake.

##\omega_b = \sqrt{8.2 +2(\frac{2\pi}{1.5})^2}##
Right.
 
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