Does CP Violation Influence Entropy Through Altered Thermal Radiation?

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CP violation leads to T-violation, which disrupts Kirchhoff's law of thermal radiation, affecting the absorption and emission rates of particles. In a thermal equilibrium scenario, a body can become either hotter or colder than its environment based on the probabilities of absorption versus emission. However, the transition probabilities in quantum physics are influenced by both the asymmetric probability amplitude and the phase-space factor, with the latter dominating and aligning with the second law of thermodynamics. While small T-violations may not significantly impact thermodynamic behavior, there is speculation about the potential for creating a perpetuum mobile of the second kind in small mesoscopic systems. The discussion also touches on the relationship between the Standard Model's structure and phase space partitioning, raising questions about the nature of this definition as information.
tzimie
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Please help me with my confusion.
My logic:
1. CP violation causes direct T-violation
2. T-violation breaks Kirchhoff's law of thermal radiation (imagine a rock in a thermal bath of T-violating particles, where absorption and emission rates are different). When I say "radiation", I don't mean photons, but any type of radiation.
3. Such body in thermal equilibrium with environment will become hotter or colder than environment, depending on what is more probable - absorption or emission.
4. !?
 
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Will the rock become hotter or colder than the environment? Wouldn't the rate of absorption of T-violating particles equal the emission of T-violating antiparticles?
 
Khashishi said:
WWouldn't the rate of absorption of T-violating particles equal the emission of T-violating antiparticles?

No, because you are describing the CT symmetry, which is also violated.
 
tzimie said:
3. Such body in thermal equilibrium with environment will become hotter or colder than environment, depending on what is more probable - absorption or emission.
Transition probability in quantum physics depends on two factors. One factor is the probability amplitude, which is asymmetric for absorption/emission in T-violating processes. But the other factor which you might overlook is the phase-space factor; the transition to a larger phase space is more probable. It is this second factor which is responsible for the second law in thermodynamics, and the small T-violation in the first factor cannot significantly influence the dominating effect of the second factor.
 
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Demystifier said:
Transition probability in quantum physics depends on two factors. One factor is the probability amplitude, which is asymmetric for absorption/emission in T-violating processes. But the other factor which you might overlook is the phase-space factor; the transition to a larger phase space is more probable. It is this second factor which is responsible for the second law in thermodynamics, and the small T-violation in the first factor cannot significantly influence the dominating effect of the second factor.

Agreed, but still you will be able to create perpetuum mobile of the second kind, right?
 
tzimie said:
Agreed, but still you will be able to create perpetuum mobile of the second kind, right?
Perhaps only far small mesoscopic systems.
 
with respect to post #4

Is the partition of the phase space a direct result of the SM?

If I understand correctly the apparent structure of the SM gives it a specific phase space partitioning that sets egodic probabilities, but from what is that structure defined? Is its definition considered information?
 
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