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## Homework Statement

There's a block on a ramp. The block weighs 48.9 kg and the ramp's theta (the angle the ramp makes to the ground) is 45. Assumng gravity is 9.8 m/s^2, how would i find the force of the block parallell to the ramp?

## Homework Equations

Um..maybe

F=(mu)(m)(g)

F=(mu)(normal force)

or F=ma

and all 4 kinematics equations:

D=((vi+vf)/2)*t

vf=vi+at

D=vi*t+((at^2)/2)

vf^2=vi^2+2(a)(d)

## The Attempt at a Solution

So first i drew it out. the block is accelerating down the ramp, and for the FBD i found the force of gravity acting straight down (Which can be broken down into two vectors, one perpendicular to the ramp and one parallel to it), the normal force perpendicular to the slope, the acceleration downwards, and the friction backwards.

Then i'm totally baffled. Am i supposed to use the kinematics equations to find acceleration to find the block's force or soh cah toa to find his friction?

And sorry if i'm doing this wrong, this is my first post and i'm one confused little boy.