Crazy Projectile Motion Problem Coming Right At Yah

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Homework Help Overview

The discussion revolves around a projectile motion problem involving a rocket. The original poster seeks to find the initial velocity and maximum height given specific parameters, including a vertical launch angle and a time duration.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the known quantities and unknowns, emphasizing the vertical nature of the motion due to the 90° angle. Various equations of motion are referenced, and questions arise regarding the implications of zero initial and final velocities. There is also exploration of how to determine the maximum height from the given information.

Discussion Status

Participants are actively engaging with the problem, offering insights and questioning assumptions. Some guidance has been provided regarding the use of equations of motion, and there is a recognition of the need to clarify the nature of the projectile's motion. Multiple interpretations of the problem are being explored without a clear consensus on the next steps.

Contextual Notes

There is an ongoing discussion about the definitions and assumptions related to the motion of the rocket, particularly regarding its classification as a projectile versus a self-propelling rocket. The time duration and vertical launch angle are critical parameters under consideration.

loopsnhoops
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Homework Statement



Find the initial velocity and the maximum height of the rocket.

Angle = 90˚
Horizontal distance = 0 m
Time = 6.55 seconds

Homework Equations



Suvat equations.

The Attempt at a Solution



s = ut + 1/2a(t^2)
s = 6.55u
0/6.55 = u

?

Please help!
 
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It would help to write down the known quantities and the unknowns:

v, t and a are known. Since the angle is 90°, there is no horizontal component involved. The unknowns are u and S. Thinking of equations where only one of the unknowns is used will help.
 
v = u + at?

but how does that work I would get

0 = 0 + 0(6.55)
 
If both initial and final velocities are zero and the acceleration is zero, how does the rocket move?

u cannot be zero since that is what you are supposed to find . What is the velocity (final velocity) of the rocket at its maximum height? What is its acceleration?
 
Thanks so far i got u which is 32.75 I think but I don't know how to find the maximum height.
 
Funny that they call it a rocket. Rockets are usually self propulsive by hurling mass backwards. This is a normal projectile, right? :)
 
s = vt + 1/2a(t^2).

here you have a solution for s. if you plug in s=0 (the ground where the projectile starts), you probably have two different t that satisfy this. One is obviously t=0, but the other?.

As for the maximum height; well, what you have here is distance as a function of time s(t). What about finding the maximum value of this graph? ;)
 

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