# Critical Exponents in the 1D Ising Model

1. Sep 30, 2014

### MisterX

1. The problem statement, all variables and given/known data
Obtain the critical exponents for specific heat, susceptibility, and the order parameter (magnetization).

2. Relevant equations
$$A = -k_B T N \ln \left[e^{\beta J} \cosh (\beta h) +\sqrt{ e^{2\beta J}\sinh^2 \beta h + e^{-2\beta J} }\right]$$
$$\left<m \right> \propto \frac{\partial A}{\partial h} \to \frac{\sinh (\beta h)}{\sqrt{\sinh ^2(\beta h)+e^{-4 \beta J}}}$$
$$\chi_T = \left(\frac {\partial \left<m \right>}{\partial h} \right)_T = \frac{\beta \cosh (\beta h)}{\sqrt{\sinh ^2(\beta h)+e^{-4 \beta J}}}-\frac{\beta \sinh ^2(\beta h) \cosh (\beta h)}{\left(\sinh ^2(\beta h)+e^{-4 \beta J}\right)^{3/2}}$$

3. The attempt at a solution
I can understand how to derive these various expressions above but I don't know how to determine the critical exponent using them. The "base" for this exponent shold be $e^{-\beta J}$.

So I need to show for example $\chi \sim \left( e^{-\beta J}\right)^p$ as $\beta \to 0$. I have tried using the formal definition of asymptotic and found exponent 0 for magnetization, but I'm not sure this is correct. Also it appears for the susceptibility there is no value of p for which the susceptibility will be asymptotic. So maybe they critical exponents come from a looser definition then asymptoticity?

2. Sep 30, 2014

### MisterX

Sorry that should be $\beta\to \infty$