Find Critical Numbers: Easier Way to Solve

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SUMMARY

The discussion focuses on finding critical numbers in calculus, specifically through the process of taking the derivative of a function and setting it to zero. Participants confirm that critical points occur where the derivative equals zero or is undefined, distinguishing them from points of inflection, which relate to the second derivative. An example provided is the function y = x^2 + x, where the critical number is found to be x = -1/2. Another example illustrates that for the function f(x) = x^3 - 3x, the critical point is x = 1, with the inflection point at x = 0.

PREREQUISITES
  • Understanding of basic calculus concepts, including derivatives and critical points.
  • Familiarity with the first and second derivative tests.
  • Knowledge of polynomial functions and their properties.
  • Ability to solve algebraic equations.
NEXT STEPS
  • Study the process of finding critical points using the first derivative test.
  • Learn about the second derivative test for determining concavity and points of inflection.
  • Explore polynomial function behavior and graphing techniques.
  • Practice solving various functions to identify critical and inflection points.
USEFUL FOR

Students and educators in mathematics, particularly those studying calculus, as well as anyone interested in understanding the behavior of functions through critical points and inflection points.

afcwestwarrior
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how do you find critical numbers, and do you have to keep on plugging in a number until you find zero or is their an easier way
 
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i know the theorem already
 
What theorem are you referring to?

You take the derivative of the function, set it equal to zero, and solve.
 
usually we take derivative of function and set it equal to 0 like hage567 said
for example you consider this function
y=x.x+x=x(2)+x
y'=dy/dx
y'=2x+1
for finding the critical number we set it to zero
y'=0
=> 2x+1=0
=> 2x=-1
=> x=-1/2
-1/2 is critical number for this function
and one of its usage is for finding the MAX. and MIN. of a function.
 
Aren't points of inflection also critical points?
 
No. Critical points are where either the derivative is 0 or where the derivative does not exist. Points of inflection are where the secondderivative changes sign. That has to be where the second derivative is 0 or does not exist although not all such points are inflection points.

For example, if f(x)= x3- 3x, then df/dx= 3x2- 3 so the critical points are x= 1 while d2f/dx2= 6x. The only inflection point is at x= 0.
 

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