Cross product in cylindrical coordinates

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Homework Help Overview

The discussion revolves around the cross product in cylindrical coordinates, specifically examining the relationship between the unit vectors \(\hat{z}\), \(\hat{R}\), and \(\hat{\phi}\). Participants are trying to understand the implications of a textbook equation involving these vectors and the sine function in the context of the cross product.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are exploring the definition of the cross product and questioning how the sine function arises in the context of the given equation. There is also an attempt to compute the cross product using a matrix method, leading to confusion regarding the expected direction and magnitude.

Discussion Status

Some participants are seeking clarification on the definitions and relationships between the vectors involved, while others are questioning the assumptions made in the textbook. There is an ongoing exploration of the implications of the equations presented, with no clear consensus yet.

Contextual Notes

One participant notes the need for more information from the textbook to clarify the context of the equations. There is also a mention of the angle \(\theta\) between \(\hat{R}\) and the z-axis, which may influence the interpretation of the cross product.

fishingspree2
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In my physics textbook we have
d\vec{l}=\hat{z}dz
and then it says
d\vec{l}\times \hat{R}=\hat{\phi}\sin \left (\theta \right )dz

How so? What is \hat{z}\times\hat{R}? If it is \hat{\phi} then where does the sine come from?
 
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Check the definition of cross product.
 
SteamKing said:
Check the definition of cross product.
If i use the fact that a X b = |a| |b| sin(theta) then I understand where the sine comes from, it this case it would also mean that z X R is in the φ direction if d\vec{l}\times \hat{R}=\hat{\phi}\sin \left (\theta \right )dz is correct.

but when I compute z X R using the 3x3 matrix
R φ z
0 0 1
1 0 0

I get +φ, and there is no sine.
 
Any idea what am I missing?
 
You have a big advantage on anyone commenting here: You are pulling some equation from your (unnamed) physics textbook. How about showing us a little more information?
 
It looks like \hat{z} is a unit vector in the axial direction, \hat{\phi} is a unit vector in the circumferential direction, \hat{R} is a unit vector pointing from the origin in an arbitrary spatial direction, and \theta is the angle between the unit vector \hat{R} and the z axis.

\hat{R}=\sin(\theta)\hat{r}+\cos(\theta)\hat{z}

where \hat{r} is a unit vector in the radial coordinate direction.
 

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