1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Cross Product in Uniform Circular Motion

  1. Jul 7, 2007 #1
    1. The problem statement, all variables and given/known data

    A centripetal-acceleration addict rides in uniform circular motion with period T = 3.22 s and radius r = 3.00 m. At one instant his acceleration is a = (7.00 m/s2) i + (-9.00 m/s2) j. At that instant, what are the following values?

    (b) r X a





    3. The attempt at a solution

    I'm really stumped on this one. I completely understand how to do cross products of a vector, but there is nothing in my text book about doing a cross product problem in uniform circular motion. I tried taking the magnitude of a and multiplying it to times r, but that wasn't right. If anyone can give me a hint as to how to start this, I would be very thankful.
     
  2. jcsd
  3. Jul 7, 2007 #2

    nrqed

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    what do you know about the acceleration vector in uniform circular motion?
     
  4. Jul 7, 2007 #3
    - I know that acceleration is always concentrated toward the center and is always perpendicular to the objects velocity. I know that a=v^2/r . I think that's about it...
     
  5. Jul 7, 2007 #4

    nrqed

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    Right. So in the formula [itex] \vec{r} \times \vec{a} [/itex], assuming that by the vector "r" they mean the vector pointing from the center of the circle to the position of the object, you know that these two vectors point in opposite directions. What can you say about the cross product of two vectors pointing in opposite directions?
     
  6. Jul 7, 2007 #5
    that their product would be 0. Thanks for the help. I just wish the textbook explained things worth a crap.
     
  7. Jul 7, 2007 #6

    nrqed

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    You're welcome. When you have questions about the cross product, there are two ways to go: through components or through the formula "magnitude of a times magnitude of b times sin (theta)".
    Then think about all the information that you know about either the magnitudes of the vectors or their direction.


    best luck!
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Cross Product in Uniform Circular Motion
Loading...