Gavroy Messages 232 Reaction score 0 Thread starter Mar 26, 2011 #1 hi i am just doing some quantum mechanics. unfortunately, i have spent the last 2 hours on one single step, which i do not understand at all. i don't get it, how you get from (19) to (20) in the attached file? could somebody explain this to me? Attachments Datei.pdf Datei.pdf 585.9 KB · Views: 322
hi i am just doing some quantum mechanics. unfortunately, i have spent the last 2 hours on one single step, which i do not understand at all. i don't get it, how you get from (19) to (20) in the attached file? could somebody explain this to me?
jtbell Staff Emeritus Science Advisor Homework Helper 2025 Award Messages 16,110 Reaction score 8,395 Mar 26, 2011 #2 It might help people in deciding whether to download the PDF, to know that your question is about a fairly advanced topic: calculating the van der Waals forces between two hydrogen atoms in the ground state. (Unfortunately I can't help.)
It might help people in deciding whether to download the PDF, to know that your question is about a fairly advanced topic: calculating the van der Waals forces between two hydrogen atoms in the ground state. (Unfortunately I can't help.)
Bill_K Science Advisor Insights Author Messages 4,159 Reaction score 207 Mar 26, 2011 #3 Isn't it just straightforward? If there's something subtle, I'm missing it too. Σi |<Bi|Q|A>|2 = Σi <A|Q| Bi><Bi|Q|A> Completeness says Σi |Bi><Bi| = I so the result is <A|Q2|A>
Isn't it just straightforward? If there's something subtle, I'm missing it too. Σi |<Bi|Q|A>|2 = Σi <A|Q| Bi><Bi|Q|A> Completeness says Σi |Bi><Bi| = I so the result is <A|Q2|A>
Gavroy Messages 232 Reaction score 0 Mar 26, 2011 #5 sorry, I overlooked something: Bill_K said: Σi |<Bi|Q|A>|2 = Σi <A|Q| Bi><Bi|Q|A> could you explain this relation to me? Last edited: Mar 26, 2011
sorry, I overlooked something: Bill_K said: Σi |<Bi|Q|A>|2 = Σi <A|Q| Bi><Bi|Q|A> could you explain this relation to me?
dextercioby Science Advisor Insights Author Messages 13,419 Reaction score 4,227 Mar 26, 2011 #6 Well, you know that in algebra [itex]z z^{*} = |z|^2[/itex], right ? Now pick [itex]z= \langle A|Q|B_i\rangle[/itex].
Well, you know that in algebra [itex]z z^{*} = |z|^2[/itex], right ? Now pick [itex]z= \langle A|Q|B_i\rangle[/itex].