Current Carrying Wire in Magnetic Field

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SUMMARY

The discussion focuses on calculating the total magnetic force acting on a current-carrying loop in a magnetic field. The relevant equations used include the magnetic force formula \( f_{m} = IL \times B \) and the magnetic field equation \( B = \frac{μ_{0} \cdot I}{2\pi \cdot R} \). The calculated magnetic fields for the top and bottom wires are \( B = 0.0001 \) T and \( B = 0.00004 \) T, respectively. The forces acting on the top and bottom of the wire are \( F_{m} = 0.00004 \) N and \( F_{m} = 0.0000016 \) N, leading to a need for further analysis of the net force on the loop.

PREREQUISITES
  • Understanding of magnetic fields and forces in physics
  • Familiarity with the Biot-Savart Law
  • Knowledge of vector cross product operations
  • Basic algebra for manipulating equations
NEXT STEPS
  • Calculate the net force on the loop considering all sides
  • Explore the implications of wire orientation on magnetic force
  • Study the Biot-Savart Law for magnetic field calculations
  • Investigate the effects of varying current on magnetic force
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding the behavior of current-carrying conductors in magnetic fields.

DeChance
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Homework Statement


Find the total magnetic force acting on the loop
http://tinypic.com/r/2yvvyuw/5

Homework Equations


f_{m} = IL X B
B =\frac{μ_{0}*I}{2∏*R}


The Attempt at a Solution


Magnetic Field from Wire at Top
B = \frac{4∏*10^{-7}*10}{2∏*2*10^{-2}}
B = .0001

Magnetic Field from Wire at Bottom
B = \frac{4∏*10^{-7}*10}{2∏*5*10^{-2}}
B = .00004

Force on top of wire
F_{m} = 8*5*10^{-2}*.0001
F_{m} = .00004

Force on bottom of wire
F_{m} = 8*5*10^{-2}*.00004
F_{m} = .0000016


Hello everyone! Heard about you awesome guys from a classmate, kinda late in the semester but better late than never :-p. At this point I'm not sure what to do. I assume the two sides that are parallel to each other will cancel each other out at this point, but I'm not sure. Also I wanted to be sure the formulas I used were used properly above!
 

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Your equations look right.
DeChance said:
I assume the two sides that are parallel to each other will cancel each other out
If you mean the two of length 3cm, yes. (Which way will the forces act on them?)
You are asked for the net force on the loop, but you have only posted the forces on the upper and lower parts of the loop separately. What is the net force, and which way will it act?
 

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