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Current Carrying Wire in Magnetic Field

  1. May 11, 2013 #1
    1. The problem statement, all variables and given/known data
    Find the total magnetic force acting on the loop
    http://tinypic.com/r/2yvvyuw/5

    2. Relevant equations
    f[itex]_{m}[/itex] = IL X B
    B =[itex]\frac{μ_{0}*I}{2∏*R}[/itex]


    3. The attempt at a solution
    Magnetic Field from Wire at Top
    B = [itex]\frac{4∏*10^{-7}*10}{2∏*2*10^{-2}}[/itex]
    B = .0001

    Magnetic Field from Wire at Bottom
    B = [itex]\frac{4∏*10^{-7}*10}{2∏*5*10^{-2}}[/itex]
    B = .00004

    Force on top of wire
    F[itex]_{m}[/itex] = 8*5*10[itex]^{-2}[/itex]*.0001
    F[itex]_{m}[/itex] = .00004

    Force on bottom of wire
    F[itex]_{m}[/itex] = 8*5*10[itex]^{-2}[/itex]*.00004
    F[itex]_{m}[/itex] = .0000016


    Hello everyone! Heard about you awesome guys from a classmate, kinda late in the semester but better late than never :tongue:. At this point I'm not sure what to do. I assume the two sides that are parallel to each other will cancel each other out at this point, but I'm not sure. Also I wanted to be sure the formulas I used were used properly above!
     

    Attached Files:

  2. jcsd
  3. May 11, 2013 #2

    haruspex

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    Your equations look right.
    If you mean the two of length 3cm, yes. (Which way will the forces act on them?)
    You are asked for the net force on the loop, but you have only posted the forces on the upper and lower parts of the loop separately. What is the net force, and which way will it act?
     
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