Current flowing in a cylinder and induced EMF

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Homework Help Overview

The discussion revolves around the behavior of current flowing in a cylinder and the induced electromotive force (EMF) associated with it. Participants explore the relationship between current, resistance, and magnetic fields, particularly in the context of a cylindrical conductor and its comparison to a solenoid.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants examine the induced EMF in relation to changing current and magnetic fields, questioning the correctness of equations and assumptions about the magnetic field configuration. There is a discussion about the equivalent resistance of the cylinder and how it relates to the current flowing through it.

Discussion Status

Some participants have provided guidance on the interpretation of magnetic fields in relation to solenoids and cylindrical conductors. There is an ongoing exploration of the implications of the equations presented, with some participants questioning the signs and assumptions made in the original equations.

Contextual Notes

Participants are navigating through the complexities of the problem, including the assumptions about the magnetic field and the configuration of the cylinder. There is a mention of potential sign issues in the equations, indicating a need for careful consideration of the relationships between current, resistance, and induced EMF.

Jahnavi
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Homework Statement


cylinder.png

options.png


Homework Equations

The Attempt at a Solution



The current will decrease , as a result an EMF will be induced in the cylinder .

The EMF induced E = -dΦ/dt

I am assuming magnetic field through the cylinder to be same as that at the center of the a current carrying coil which is given by μ0i/2r .

E = -μ0πrdi/(2dt)

I tried to calculate equivalent resistance .

I think we can consider thin cylinder material as a thin sheet of breadth 'l' , length '2πr' and thickness 'd' .

It can be divided into thin wires of length '2πr' , width dx and thickness 'd'

Current is flowing across the breadth .

Consider a very thin section of wire of width dx at a distance x across the breadth from one end .

All these thin wires are in parallel .

Their equivalent resistance turns out to be ρ2πr/ld .

So , the resistance across which the current is flowing is R = ρ2πr/ld .

The current equation would be iR + E = 0 .

iR - μ0πrdi/(2dt) = 0

ρ2πri/ld - μ0πrdi/(2dt) = 0

Is the equation correct ?
 

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Why is the current equation iR + E = 0? Should it not be iR = E?
 
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Jahnavi said:
I am assuming magnetic field through the cylinder to be same as that at the center of the a current carrying coil which is given by μ0i/2r .
No. Think solenoid.

So , the resistance across which the current is flowing is R = ρ2πr/ld .
That looks good to me.

The current equation would be iR + E = 0 .

iR - μ0πrdi/(2dt) = 0

As @Chandra Prayaga pointed out, there seems to be a sign problem here. Note that your equation would imply that di/dt is positive; i.e., the current would increase instead of decrease.
 
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Thank you TSny .

TSny said:
No. Think solenoid.

You are right :smile:

Magnetic field inside a solenoid is μ0ni .

How would I find 'n' of the equivalent solenoid ? 'n' is the number of terms per unit length .
 
Solenoid consists of wires. This cylinder has a continuous current distribution thus evaluate using Ampere's circuital law.

B.2πr = μ0
That gives B =μ0i/2πr
 
Note that in ##\mu_0ni##, ##\, i## is the current in one turn. Try to interpret the meaning of ##ni##.
 
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TSny said:
Note that in ##\mu_0ni##, ##\, i## is the current in one turn. Try to interpret the meaning of ##ni##.

Wow !

I didn't think in this way .

Magnetic field inside cylinder would be μ0i/l .

This gives us option 2) .

Is that correct ?
 
Jahnavi said:
Magnetic field inside cylinder would be μ0i/l .

This gives us option 2) .
Yes. Good work.
 
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Thank you so much :smile:
 

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