Current from a sine wave signal

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SUMMARY

The discussion focuses on calculating the current through a 10 kilo-Ohm resistor connected to a 20V peak-to-peak sine wave signal. The peak current (Imax) is determined to be 1 mA, calculated using the formula Imax = Vp/R, where Vp is 10V. The root mean square (Irms) current is calculated as approximately 707 µA using the formula Irms = Vrms/R, with Vrms derived from the peak voltage. The average current for a sine wave is established as zero, as the positive and negative halves cancel each other out over one complete cycle.

PREREQUISITES
  • Understanding of Ohm's Law (V=IR)
  • Knowledge of sine wave characteristics
  • Familiarity with root mean square (RMS) calculations
  • Basic electrical engineering principles
NEXT STEPS
  • Research the concept of average current in AC signals
  • Learn about the power rating calculations for resistors
  • Explore the implications of RMS values in AC circuit analysis
  • Study the behavior of sine waves in different load conditions
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in AC circuit analysis and resistor selection for sine wave applications.

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Homework Statement


Given a sine wave signal (20V PP) connected to a 10 kilo-Ohm resistor. Calculate the current through the resistor in terms of average, rms, and peak currents. What wattage rating should the resistor have?


Homework Equations


Vrms=(1/Sqrt(2))(Vp)
V=IR

The Attempt at a Solution



For peak I'm assuming that since peak voltage means peak current, we would find the peak current by:

Vp=IR where Vp=Vpp/2=20/2=10V

So: Imax=(10V)/(10E3)= 1E-3 A

Since Vrms=Vp/sqrt(2)

Irms=Vrms/R=(10/sqrt(2))/(10E3)=7.07E-4A

I don't know how to fine I average though...

Any help would be great!
 
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