Current in cell during a certain period

Click For Summary
SUMMARY

The discussion focuses on calculating the current in an electrolytic cell based on the deposition of gold. Given that 3.9x10^-3 grams of gold is deposited over a period of 2.67 hours, the calculation involves determining the number of gold atoms using the molar mass of gold (197 g/mol) and Avogadro's number (6.022x10^23 atoms/mol). The total charge transferred is then calculated using the elementary charge (1.6x10^-19 C) and the current is derived using the formula I = charge/time.

PREREQUISITES
  • Understanding of molar mass and Avogadro's number
  • Knowledge of elementary charge (1.6x10^-19 C)
  • Familiarity with the formula for current (I = charge/time)
  • Basic concepts of electrolytic cells
NEXT STEPS
  • Calculate the number of gold atoms deposited using the formula: number of atoms = (mass of gold / molar mass) x Avogadro's number
  • Determine the total charge transferred by multiplying the number of gold atoms by the elementary charge
  • Use the formula I = charge/time to find the current in the cell
  • Explore further examples of current calculations in electrolytic cells
USEFUL FOR

Chemistry students, electrochemists, and anyone involved in practical applications of electrolytic cells will benefit from this discussion.

eagle63903
Messages
1
Reaction score
0
Does anyone know how to do this problem? I cannot find any examples in my book like it, and I have gotten no where in a full hour.

If 3.9x10^-3 of gold is deposited on the negative electrode of an electrolytic cell in a period of 2.67 h, what is the current in the cell during this period? Assume that the gold ions carry one elementary unit of positive charge.

Round your answer to three significant figures. The molar mass of gold is 197g/mol Avogadro's number is 6.022x10^23 atoms/mol The elementary change is 1.6x10^-19 C.


Any help would be appriciated, especially a step by step analysis if you could.

Thanks
eagle63903
 
Physics news on Phys.org
eagle63903 said:
Does anyone know how to do this problem? I cannot find any examples in my book like it, and I have gotten no where in a full hour.

If 3.9x10^-3 of gold is deposited on the negative electrode of an electrolytic cell in a period of 2.67 h, what is the current in the cell during this period? Assume that the gold ions carry one elementary unit of positive charge.

Round your answer to three significant figures. The molar mass of gold is 197g/mol Avogadro's number is 6.022x10^23 atoms/mol The elementary change is 1.6x10^-19 C.


Any help would be appriciated, especially a step by step analysis if you could.

Thanks
eagle63903

You have to break up the solution in two steps.

First step: if you know the mass of gold that was deposited, you should be able to calculate the actual number of gold atoms that were deposited (this is where the molar mass and Avogadro`s number comes into play). Do you know how to do that? (no need to worry about charge or current in that step)

Second step: once you know the number of atoms that were deposited, you know the total charge that was transferred and you use I=charge/(time interval)

Pat
 

Similar threads

Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K