If 3.50 x 10^-3 kg of gold is deposited on the negative electrode of an electrolytic cell in a period of 2.99 h, what is the current in the cell during that period? Assume that the gold ions carry one elementary unit of positive charge. (A)
I = DeltaQ/DeltaT
I = DeltaV/R (I don't think this is needed)
The Attempt at a Solution
Well, I have been reading the book and asked a friend who had taken physics before but was not able to figure this out.
I believe I have to use the formula I = DeltaQ/DeltaT, but not sure how I would use it as in would deltaT be 2.99 h x 60? I said that because when I used it before it was always min x 60 sec.
My main problem is I never encounter where a given is in mass form with an element such as gold. How would I convert 3.50 x 10^-3 kg into a number to fit into as equation to solve for A (current).
Please help me or give me some tips on where to start.