A magnetic field is perpendicular to the plane of a single-turn circular coil. The magnitude of the field is changing, so that an emf of 0.91 V and a current of 3.2 A are induced in the coil. The wire is the re-formed into a single-turn square coil, which is used in the same magnetic field (again perpendicular to the plane of the coil and with a magnitude changing at the same rate).
What emf and current are induced in the square coil?
L = 2*pi*r, A = L/4*pi, A = L^2/16
The Attempt at a Solution
Okay i know the lengths are the same for the circular coil and the square coil. Oh and the form has changed.
So A1/A2 = (L^2/4*pi) / (L^2/16) = 16/4*pi
and for the current i could use I2 = V2/R
and i'm not sure but i think R = V1/I1 ?
I have alot of help so far, not sure what the final answer is, anyone?