Current produced by varying magnetic flux

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SUMMARY

The discussion focuses on calculating the magnitude of the current produced by a varying magnetic flux in a system with an upper circumference radius of 5 cm and a lower circumference radius of 9 cm. Given a resistance of 3.00 ohm/meter and a magnetic field change rate of 2.00 T/s, the electromotive force (EMF) can be determined using the equation EMF = -N (dΦ_B/dt). The current direction is established by Lenz's Law, which states that the induced current will oppose the change in magnetic flux.

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Knowledge of Lenz's Law
  • Familiarity with Ohm's Law (V = RI)
  • Basic concepts of magnetic flux (Φ_B)
NEXT STEPS
  • Calculate the induced EMF using the provided parameters
  • Explore the implications of Lenz's Law on current direction
  • Investigate the relationship between resistance and current in varying magnetic fields
  • Learn about practical applications of electromagnetic induction in engineering
USEFUL FOR

Students studying electromagnetism, physics educators, and engineers working with electromagnetic systems will benefit from this discussion.

Tosh5457
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I'm translating the problem, so sorry for the errors.

Homework Statement


Radius of the upper circumference = 5cm
Radius of the lower circumference = 9cm
Resistance/meter = 3.00 ohm/meter
B is the magnetic field: DB/dt = 2.00 T/s

What's the magnitude of the current, and where does the current points to?

Homework Equations



EMF = [itex]-N \ \frac{\Delta \Phi_B}{\Delta t} \ \ \mbox{or} \ \ -N \ \frac{d\Phi_B }{dt}[/itex]
V = RI

The Attempt at a Solution

 

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Well, find the magnetic flux from the external field; the current should be produced in order to oppose an change in magnetic flux.
 

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