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## Homework Statement

By applying kirchhoffs rules, show that the in the RL circuit is given by: [tex]I=\frac{\epsilon}{R}\left(1-e^{-\frac{Rt}{L}}\right)[/tex]

## Homework Equations

kirchhoff's second rule: [tex]\epsilon-IR-L\frac{dI}{dt}=0[/tex]

## The Attempt at a Solution

[tex]\epsilon=IR+L\frac{dI}{dt}[/tex]

[tex]{\epsilon}dt=IRdt+LdI[/tex]

[tex]\frac{\epsilon}{I}dt-Rdt=L\frac{1}{I}dI[/tex]

then i thought to integrate both sides, LHS w.r.t t and RHS w.r.t I, but doing this on paper doesnt get to the right answer, am i going wrong somewhere with the rearranging??