(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The shape of the arch is defined by a sine function with a = 0.2 and the width of the arch is 1m. The velocity v is constant at 2m/s. What is the velocity at point P when x=0.25m?

3. The attempt at a solution

So since v is just in the x-direction, I figured that's the v_{x}speed.

Then I came to having to find an equation to v_{y}and this is where I get stuck. I remember from high school physics that equation of velocity can be essentially found by taking a derivative of the position equation.

In this case I get:

v_{y}=y'=0.2*pi*cos(pi*x)

From which I can find that at x=0.25m, v_{y}= 0.444288 m/s

But that combined with the horizontal speed of 2m/s gives me a resultant velocity of 2.05ish, instead of 2.19 that I'm supposed to get. Help please?

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# Homework Help: Curved slit - angular motion

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