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Find the speed of the particle after 0.2 seconds

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  1. Oct 30, 2016 #1
    1. The problem statement, all variables and given/known data
    The particle is thrown horizontally with speed 10 m/S (I believe from a height). Find the speed of it after 0.2 seconds.

    2. Relevant equations
    vx=v
    vy=gt
    v=sqrt(vx^2+vy^2)


    3. The attempt at a solution
    vx=10
    vy=10*0.2=2
    v=sqrt(100+4)=10.198m/S Am i right?
     
  2. jcsd
  3. Oct 31, 2016 #2
    Looks right to me. I think it is probably more common to use 9.8 ms-2 for gravity though.
     
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