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## Homework Statement

The particle is thrown horizontally with speed 10 m/S (I believe from a height). Find the speed of it after 0.2 seconds.

## Homework Equations

vx=v

vy=gt

v=sqrt(vx^2+vy^2)[/B]

## The Attempt at a Solution

vx=10

vy=10*0.2=2

v=sqrt(100+4)=10.198m/S Am i right?