1. The problem statement, all variables and given/known data A hollow aluminum cylinder with a depth of 20.0 cm has an internal capacity of 2.000 L at 20.0 C. It's full with mineral turpentine, at 20.0 C. The two of them are heated slowly, until the temperature reaches 80.0 C. a) How much of the mineral is spilled outside the cylinder? b) How much mineral remains inside? c) If the cylinder with the mineral from (b) is then again frozen to 20.0 C, how much wouldthe mineral be bellow the top of the cylinder? 2. Relevant equations ΔL = αLiΔT ΔV = βViΔT β = 3α Aluminum: a = 4*10-6 C-1 Mineral: a = 9.0*10-4 C-1 3. The attempt at a solution At first I figured I'd take the second formula, with Vi(mineral) = Vi(cylinder) = 2 L, find the Vf in both cases and then find the difference. But, that's not it. I did think of treating the depth as the "L" and going with the first formula to find out how "taller" each substance got, but that didn't work either. So... any ideas? Any help is appreciated!