Cylindrical fishing reel problem using moment of inertia

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SUMMARY

The discussion focuses on solving a physics problem involving a cylindrical fishing reel with a mass of 0.85 kg and a radius of 4.5 cm, experiencing a restraining torque of 1.6 N·m and an angular acceleration of 66 rad/s². The moment of inertia (I) is calculated using the formula I = 0.5mr², resulting in a value of 8.606 kg·m². The relationship between torque (T), angular acceleration (a), and moment of inertia (I) is established with the equation T = a * I, leading to the determination of the force exerted by the fish on the line and the length of line unwound in 0.5 seconds.

PREREQUISITES
  • Understanding of moment of inertia (I = 0.5mr²)
  • Knowledge of torque and angular acceleration relationships
  • Familiarity with rotational kinematics
  • Ability to convert between radians and degrees
NEXT STEPS
  • Study the relationship between torque and angular acceleration in rotational dynamics
  • Learn about calculating the length of unwound line using angular displacement
  • Explore the implications of friction in rotational systems
  • Review the principles of kinematics in both linear and rotational contexts
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Students studying physics, particularly those focusing on mechanics and rotational dynamics, as well as educators seeking to enhance their understanding of real-world applications of these concepts.

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Homework Statement


A cylindrical fishing reel has a mass of 0.85 kg and a radius of 4.5 cm. A friction clutch in the reel exerts a restraining torque of 1.6 N·m if a fish pulls on the line. The fisherman gets a bite, and the reel begins to spin with an angular acceleration of 66 rad/s2.
a) Find the force of the fish on the line.
b) Find the amount of line that unwinds in .5 seconds.


Homework Equations


I = .5mr^2
theta = .5at^2


The Attempt at a Solution


I found the moment of inertia to be 8.606. What I don't understand is how to relate the torque to the moment of inertia. I don't know if my calculator should be set to radians or degrees, but I tried both ways and got them both wrong.
 
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First of all I needs to be calculated with the radius as .045. That makes your I off by a factor of 104

I = 8.6*10-4

T = a*I

So accounting for the force on the line and the restraining force ...

F*.045 = 1.6 + 66*8.6*10-4

You have the right equation for b. Just remember that since θ is in radians, you need to provide θ*r for the length of line that reels off.
 
Alright thanks so much! I understand how to do it now!
 

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