Fish Pulling on Reel: Angular Accel. & Line Pulled

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SUMMARY

The discussion focuses on calculating the angular acceleration of a fishing reel subjected to a force of 1.8 N. The fishing reel is identified as a solid cylinder with a radius of 0.064 m and a mass of 0.80 kg. The correct formula for torque is established as Torque = Force x Radius, leading to the calculation of angular acceleration using the moment of inertia for solid cylinders. The initial attempt at calculating angular acceleration was incorrect due to misapplication of the torque formula.

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Homework Statement



A fish takes the bait and pulls on the line with a force of 1.8 N. The fishing reel, which rotates counterclockwise without friction, is a solid cylinder of radius 0.064 m and mass 0.80 kg.

(a) What is the angular acceleration vector of the fishing reel?
rad/s2

(b) How much line does the fish pull from the reel in 0.17 s?
m

Homework Equations



Torque = Inertia x angular acceleration
Inertia = 1/2 x Mass x Radius^2 (for solid cylinders/discs)
Angular Acceleration = acceleration/radius (I personally didn't think this was necessary, but then again I didn't get the right answer)


The Attempt at a Solution



I simply calculated Inertia by:

1/2 x 0.8 kg x (0.064 m)^2 = 1.6384 x 10^-3

Then I tried to calculate angular acceleration by:

1.8 N / (1.6384 x 10^-3) = 1098.63 rad/sec ^2

I was told by WebAssign that this was incorrect...so I entered it as a negative value (-1098.63) in case I was confused regarding the counterclockwise direction of the reel, but this was also considered incorrect.

I have not attempted part B yet because my approach for part B would involve knowing the angular acceleration.

Please help!
 
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Hi premedonna89, welcome to PF.
I*α = Torque = F*r.
Try this one.
 
rl.bhat said:
Hi premedonna89, welcome to PF.
I*α = Torque = F*r.
Try this one.

ah!

Torque = 1.8 x 0.064

*blush*

thank you!
 

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