1. The problem statement, all variables and given/known data A 4.00-m length of light nylon cord is wound around a uniform cylindrical spool of radius 0.500 m and mass 1.00 kg. The spool is mounted on a frictionless axle and is initially at rest. The cord is pulled from the spool with a constant acceleration of magnitude 2.82 m/s2. How much work has been done on the spool when it reaches an angular speed of 7.95 rad/s? 2. Relevant equations Angular acceleration = a/r Moment of inertia of the cylinder is mr^2 3. The attempt at a solution I solved for tension first: T*0.5 = 1*(0.5)^2*(2.82 / 0.5)=> So T=2.82 N Then using kinematic equations I solved for theta: Angular acceleration = a/r = 2.82/0.5 = 5.64 so 7.95^2 = 2 * 5.64 * theta ==> theta = 5.6 so work = 2.82 * 5.6 * 0.5 = 7.896 joules However webassign says i'm wrong, any help would be greatly appreciated as I spent too much time into this, thanks.