Derivative of s/sqrt(60s + 25) | Calculus Homework Solution

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SUMMARY

The derivative of the function s/sqrt(60s + 25) can be calculated using the product rule and chain rule of differentiation. The correct approach involves rewriting the function as s(60s + 25)^-1/2, where the product rule applies. The derivative is found by calculating da/db and db/ds, resulting in da/ds = -30s(60s + 25)^-3/2. This method ensures accurate differentiation by treating the function as a product of two distinct functions.

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Homework Statement



d/ds s/sqrt(60s + 25)

Homework Equations





The Attempt at a Solution



d/ds s/sqrt(60s + 25) = d/ds s(60s + 25)^-1/2
if a = s(60s + 25)^-1/2
and b = (60s + 25)
da/db = -1/2s(60s +25)^-3/2
db/ds = 60
da/ds = -30s(60s +25)^-3/2

Any help much appreciated.
 
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It looks like you are trying to use the chain rule, but that doesn't quite work here. The reason is that if you want to calculate da/db, you have to write a completely in terms of b, i.e. as (b - 25) / 60 * b-1/2.

Note that after the rewriting in your first line (s (60s + 25)-1/2) you have a product of two functions, i.e. you are looking for d/ds(a b) with a = s, b = (60s + 25)-1/2
 

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