SUMMARY
The derivative of the function s/sqrt(60s + 25) can be calculated using the product rule and chain rule of differentiation. The correct approach involves rewriting the function as s(60s + 25)^-1/2, where the product rule applies. The derivative is found by calculating da/db and db/ds, resulting in da/ds = -30s(60s + 25)^-3/2. This method ensures accurate differentiation by treating the function as a product of two distinct functions.
PREREQUISITES
- Understanding of calculus concepts, specifically differentiation techniques.
- Familiarity with the product rule and chain rule in calculus.
- Knowledge of rewriting functions for easier differentiation.
- Basic algebra skills for manipulating expressions.
NEXT STEPS
- Study the product rule of differentiation in detail.
- Learn about the chain rule and its applications in calculus.
- Practice rewriting complex functions for differentiation.
- Explore examples of derivatives involving square roots and polynomials.
USEFUL FOR
Students studying calculus, particularly those tackling differentiation problems involving products and composite functions.