How Does Damping Affect the Energy of an Oscillator?

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    Damped Oscillator
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SUMMARY

The discussion centers on the energy dynamics of a damped oscillator, described by the equation (m)y''(t) + (v)y'(t) + (k)y(t) = 0. Participants analyze the energy expression E = (1/2)mx'² + (1/2)kx² and its time derivative dE/dt = -mvx'. A user expresses confusion over the differentiation process, but others confirm that their calculation of dE/dt is correct. The conversation highlights the importance of unit consistency in physical equations.

PREREQUISITES
  • Understanding of differential equations, specifically second-order linear equations.
  • Familiarity with the concepts of energy in mechanical systems.
  • Knowledge of calculus, particularly differentiation techniques.
  • Basic grasp of oscillatory motion and damping effects.
NEXT STEPS
  • Study the derivation of the damped oscillator equation in detail.
  • Explore the implications of damping on energy loss in oscillatory systems.
  • Learn about the physical significance of the terms in the energy expression E = (1/2)mx'² + (1/2)kx².
  • Investigate the relationship between energy and damping coefficients in mechanical oscillators.
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Students of physics, mechanical engineers, and anyone interested in the dynamics of oscillatory systems and energy dissipation in damped oscillators.

Paddyod1509
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the damped oscillator equation:

(m)y''(t) + (v)y'(t) +(k)y(t)=0

Show that the energy of the system given by

E=(1/2)mx'² + (1/2)kx²

satisfies:

dE/dt = -mvx'


i have gone through this several time simply differentiating the expression for E wrt and i end up with

dE/dt = x'(-vx')

im at a brick wall. Am i doing something wrong? Any help is much appreciated! Thanks
 
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I have also assumed that y and x are interchangeable variables here, as no other information has been provided
 
I don't see anything wrong with your calculation. In fact, double check the units for your expressions - I don't think the suggested answer "##m\gamma \dot{x}##" even has the same units as ##dE/dt##.
 
Paddyod1509 said:
the damped oscillator equation:

(m)y''(t) + (v)y'(t) +(k)y(t)=0

Show that the energy of the system given by

E=(1/2)mx'² + (1/2)kx²

satisfies:

dE/dt = -mvx'

That must be wrong: it requires that E = C - mvx for some constant C, which is not the case.

i have gone through this several time simply differentiating the expression for E wrt and i end up with

dE/dt = x'(-vx')

That is the right expression for dE/dt.
 

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