Damping conditions for multi degrees of freedom

Click For Summary
SUMMARY

The discussion focuses on the application of damping conditions in multi-degree-of-freedom systems, specifically with two masses, three springs, and three dampers. The criteria for underdamped, overdamped, and critically damped systems are defined by the discriminant \(d^2\) in relation to \(4mk\). The equations of motion for such systems can be derived from the quadratic eigenproblem \((m + \lambda d + \lambda^2k)x = 0\). The solutions are expressed in terms of complex eigenvalues and eigenvectors, where the real part of the solution represents the physical motion of the system.

PREREQUISITES
  • Understanding of eigenvalues and eigenvectors in linear algebra
  • Familiarity with damping conditions in mechanical systems
  • Knowledge of matrix operations, specifically 2x2 matrices
  • Basic concepts of vibrations and oscillations in mechanical systems
NEXT STEPS
  • Study the derivation of the quadratic eigenproblem for multi-degree-of-freedom systems
  • Learn about the physical interpretation of complex eigenvalues in damped systems
  • Explore numerical methods for solving eigenvalue problems in mechanical engineering
  • Investigate the differences between damped and undamped vibration modes
USEFUL FOR

Mechanical engineers, students in dynamics and vibrations, and researchers focusing on multi-degree-of-freedom systems will benefit from this discussion.

gopi9
Messages
14
Reaction score
0
I know that d^2<4mk for underdamped, d^2>4mk for overdamped and d^2=4mk for critically damped. This is true if there is only 1 mass and spring and damper. How to use these equations if I have 2 mass, 3 spring and 3 dampers. That is d,m,k are in 2x2 matrices. Please some one help me with this.
 
Engineering news on Phys.org
You should specify the configuration exactly and then we can write the equations of motion!
 
In the most general case, the damped vibration modes of the system are the eigenvalues and vectors of the quadratic eigenproblem ##(m + \lambda d + \lambda^2k)x = 0##. The solutions will be of the form ##x(t) = X e^{(-\sigma + i \omega) t} ## where ##X## is a complex eigenvector, ##-\sigma + i \omega## is the complex eigenvalue, and the physical solution ##x(t)## is the real part of the right hand side of the equation. ##\sigma## represents the amount of damping, and ##\omega## the damped oscillation frequency (which is 0 for an overdamped system)

If you get lucky, the eigenvectors will be real, and the same as the eigenvectors of the undamped system ##(m - \omega_u^2 k)x = 0## (but of course the eigenvalues will be different, and the undamped frequency ##\omega_u## is not equal to the damped frequency ##\omega##).
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
992
  • · Replies 1 ·
Replies
1
Views
924
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 21 ·
Replies
21
Views
6K