I can't tell you, Brian. You know a lot more about this than I do in any case.
Some more recent Wiltshire papers. This seems to me to be a very thorough and accessible explanation of his ideas:
http://arxiv.org/pdf/1311.3787v1.pdf
and it refers to observational findings described here:
http://arxiv.org/abs/1201.5371
CKH, I can't pretend to being very interested in this alternative approach, or having more than very superficial understanding of it. I just contribute the links because your Keenan et al article did not cite Wiltshire. And his work seems relevant to the topic.
My attitude is that Lambda is a curvature constant which belongs in the Einstein equation because it is allowed by the symmetry of the theory.
\Large \bar F ={ c^4 \over 8\pi G}
\Large G_{\mu \nu} + \Lambda g_{\mu \nu} = {1\over \bar F} T_{\mu \nu}
The symmetry allows for two constants: a force (measured in Newtons) and a curvature (measured in inverse area units m
-2)
so when the equation is written it should include those two constants, one cannot a priori assume that one of them is zero.
But Lambda, the curvature constant MIGHT be zero. AFAICS there is no reason for it to be, but for many years many people thought it was, and now they think it is
Λ = 1.12 x 10
-52 m
-2
They could be wrong of course, but I think it is just as likely a priori to be that as to be zero. This does not involve any mysterious "energy". It is just a constant curvature that occurs in an equation.
The force constant that appears in the equation has a pretty well-established value which you can get, in Newtons, if you paste this into google:
c^4/(8pi G) and press return. Google will activate its calculator and say
(c^4) / (8 * pi * G) = 4.8157858 × 10
42 Newtons
Instead of Fbar let's call that force something else. Let's call that force
F
It governs the interaction of matter with geometry because it tells how much matter energy density it takes to produce a certain curvature. You multiply the curvature by
F and you get an energy density in joules per cubic meter, or equivalently in pascals, Newtons per square meter.
By our standards geometry is STIFF because it takes a big energy density to produce what is by our standards a small curvature. So
F is the stiffness of geometry, and it is a large force, by our human standards.
For example, Lambda is a small curvature. In Google code it is 1.12*10^-52 m^-2 so why not multiply it by
F and see how much energy density would be needed if (hypothetically) that curvature were not just an intrinsic built in feature of geometry but were caused by some imagined energy. So we can paste in this:
(c^4/(8pi G))*1.12*10^-52 m^-2
Google calculator will say 5.39368009 × 10
-10 pascals
That is 0.539 nanojoules per cubic meter
That is what the pretended "dark energy" density is. It is just a way of talking about a certain intrinsic curvature which cosmologists tend to assume is constant throughout all space for all time.
That's my attitude and you see it contrasts with Wiltshire and with your Keenan et al paper. they seem to think that having a small inherent constant curvature is wrong and needs to be explained away. I'd recommend just accepting it. (and don't call it an "energy")
Enough said about that.