Dashpots and the Work - Kinetic Energy Theorem

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SUMMARY

This discussion focuses on incorporating a dashpot into a work-kinetic energy analysis for a box being dragged up a ramp. The key equation presented is KA + ∫(mg)ds + ∫Tds + ∫(ks)ds + ∫μkFNds = KB, where KA and KB represent the kinetic energy at the bottom and top of the ramp, respectively. The work done by the dashpot is expressed as ∫bvds, which can be transformed into ∫bv²dt. The challenge lies in determining the integrability of these terms given the constraints of known displacement and velocity boundary conditions.

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  • Understanding of work-energy principles in classical mechanics
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  • Experience with boundary condition analysis in motion equations
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Taulant Sholla
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Homework Statement


I need to accommodate a dashpot in an intentionally simple work-kinetic energy analysis method. For example, for a box being dragged up a ramp via a rope while attached to a spring, I can deal with the work done by gravity, rope tension, spring force, and friction via the following method, along with enough known constants and sufficient displacement and velocity boundary conditions?

Homework Equations


KA+WNET=KB
... where A is the position of the box at the bottom of the ramp, and B is the position of the box at the top of the ramp.

The Attempt at a Solution


For gravity, friction, spring, and tension this becomes...
KA + ∫(mg)ds + ∫Tds + ∫(ks)ds + ∫μkFNds = KB

The work terms for the dashpot are:
∫bvds = ∫b(ds/dt)ds = ∫b(ds/dt)(ds/dt)dt = ∫bv2dt

Are any of these terms integrate-able if I'm limited to, again, only knowing displacement and/or velocity boundary conditions?
 
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Taulant Sholla said:
Are any of these terms integrate-able if I'm limited to, again, only knowing displacement and/or velocity boundary conditions?
The only way I can see is if you can write out and solve the general equation of motion. Observations of the boundary conditions should then allow you to deduce the velocity as a functionof time. That's not entirely satisfactory because it depends on theory, not pure observation.
 
Taulant Sholla said:
∫bvds = ∫b(ds/dt)ds = ∫b(ds/dt)(ds/dt)dt = ∫bv2dt
If your question is whether the work done on the dashpot is a function of some system variable, e.g. v, what does your first integral above tell you?
(Related: why is it a dumb idea to drive your car fast instead of slowly over a given distance in order to save gas?)
 

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