De broglie vs classical wavelength

In summary, the de Broglie wavelength is a characteristic "size" of a quantum particle, it's not really a super-relevant physical quantity anymore, and you can't just put it into classical wave equations to get anything physical. The wavelength for a given energy is simple based on the equation E=hf, and for electrons the wave length in terms of energy is more complicated.
  • #1
xiankai
31
0
since it is defined (from what i can tell) as h/p,

is it interchangeable with the classical wavelength in equations involving waves in general? or is it a special separate case for matter?

that is,

for photons we have the following equation:
E = hf
E = hc/λ

can the same equation be used to find the wavelength/energy of electrons?
 
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  • #2
The de Broglie wavelength is now kinda viewed as the characteristic "size" of a quantum particle. It's not really a super-relevant physical quantity anymore, nor can you just put it into classical wave equations to get anything physical.
 
  • #3
xiankai said:
since it is defined (from what i can tell) as h/p,

is it interchangeable with the classical wavelength in equations involving waves in general? or is it a special separate case for matter?

that is,

for photons we have the following equation:
E = hf
E = hc/λ

can the same equation be used to find the wavelength/energy of electrons?
For a photon E=pc, so the dB wavelength for a given energy is simple.
For an electron p=\sqrt[{E^2/c^2-m^2}, so the dB wave length in terms of energy is more complicated,.
 
  • #4
Meir Achuz said:
For a photon E=pc, so the dB wavelength for a given energy is simple.
For an electron p=\sqrt[{E^2/c^2-m^2}, so the dB wave length in terms of energy is more complicated,.

we must include the rest mass of the electron?
 
  • #5
Yes. And to get the frequency of the wave via E = hf, you must use the total energy (kinetic energy plus rest energy).
 
  • #6
According to de broglie relation lambda=h/mv ...which implies that velocity is inversely proportional to wavelength. But According to the reletion

V=n lambda ... velocity is directly proportional to wavelength... How That diffenence is Causesd ? Am i going wrong Somowhere ?
 
  • #7
Note that the wave relationship only holds for massless particles.
 
  • #8
The V in V=\nu\lambda is the phase velocity of the traveling wave packet.
This V also = E/p=h\nu/p, which is consistent.
The phase velocity is >c, but the group velocity v_G=p/E is less than c.
 

1. What is the difference between de Broglie and classical wavelength?

The de Broglie wavelength is a quantum mechanical concept that describes the wavelength of a particle, while the classical wavelength is a concept used in classical physics to describe the wavelength of a wave.

2. How do de Broglie and classical wavelengths relate to each other?

The de Broglie wavelength is derived from the momentum of a particle, while the classical wavelength is derived from the velocity and mass of a wave. However, in the limit of large masses and velocities, the de Broglie wavelength approaches the classical wavelength.

3. What is the significance of de Broglie's theory?

De Broglie's theory introduced the idea that particles, such as electrons, could exhibit wave-like properties. This helped to reconcile the seemingly contradictory behaviors of particles and waves in quantum mechanics.

4. Can de Broglie's theory be applied to macroscopic objects?

No, de Broglie's theory only applies to microscopic particles, such as electrons. Macroscopic objects have too large of a mass to exhibit wave-like behavior.

5. How is the de Broglie wavelength experimentally observed?

The de Broglie wavelength can be observed in experiments, such as the double-slit experiment, where particles exhibit interference patterns similar to waves. This confirms the wave-particle duality of quantum mechanics.

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