De Broglie Wavelength Derivation

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SUMMARY

The discussion centers on the derivation of the de Broglie wavelength, specifically the relationship L = h/p, where L represents wavelength, h is Planck's constant, and p is momentum. Participants clarify that while the equation E = hf can be manipulated to yield L = h/p, this is not a rigorous derivation but rather a postulate. The validity of applying this relationship to both massless particles, like photons, and massive particles is affirmed, emphasizing its foundational role in quantum mechanics.

PREREQUISITES
  • Understanding of Classical Mechanics, particularly kinetic energy and momentum.
  • Familiarity with quantum mechanics concepts, including Planck's constant and wave-particle duality.
  • Knowledge of the relationship between energy, frequency, and wavelength (E = hf).
  • Basic calculus, specifically differentiation, to comprehend the manipulation of equations.
NEXT STEPS
  • Study the implications of the de Broglie hypothesis in quantum mechanics.
  • Explore the concept of wave-particle duality in greater depth.
  • Learn about the derivation and applications of the Schrödinger equation.
  • Investigate the role of Planck's constant in modern physics and its significance in quantum theory.
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Students and professionals in physics, particularly those focused on quantum mechanics, as well as educators seeking to explain the foundational concepts of wave-particle duality and the de Broglie wavelength.

Goalie33
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In Classical Mechanics the derivative of Kinetic energy with respect to velocity is momentum, so I was wondering if this is valid:

In this L is lambda or wavelength and h is Planck's Constant.

E=hf, therefore E=h(v/L)
This means that dE/dv=h/L.(h and L are constants and the derivative of v would be 1.)
Rearranging this we get:
L=h/p.

I just wanted to know if this is considered valid.
 
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in E=hf, 'v' is equal to c, which is a constant!

One does not 'derive' de Broglie Wavelength, one postulates it.

E = hc/L, E/c = h/L

But E/c is the momentum of a massless particle, e.g. the photon. Hence, we postulate that this result can be more general to be valid for massive particles with momentum p.

p = h/L

So it is not a rigour derivation, but a bold postulate, which turned out to work fine :-)
 

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