De Broglie wavelength of a particle

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SUMMARY

The discussion centers on calculating the new de Broglie wavelength of a particle after its kinetic energy triples, with an initial de Broglie wavelength of 0.00 m. Participants highlight that a real particle cannot possess a de Broglie wavelength of 0.00 m, indicating a fundamental misunderstanding. The consensus suggests that if the initial wavelength is indeed 0.00 m, the new wavelength remains 0.00 m, but this scenario is unrealistic as it implies infinite momentum. Relativistic effects should not be ignored in practical applications.

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  • Understanding of de Broglie wavelength and its formula: λ = h/p
  • Basic knowledge of kinetic energy and its relation to momentum
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The problems is:

A particle has a de Broglie wavelength of 0.00 m. Then its kinetic energy triples. What is the particle's new de Broglie wavelength, assuming that relativistic effects can be ignored?


I have no idea where to begin. Please help me:bugeye:!
 
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I think you have a typo above, a real particle can't have a deBroglie wavelength of 0.00m.

Also, for future reference, questions like this (homework type questions) should be posted in the homework help section. Also, according to the forum rules, you must show some work in order to get homework help here. You must know some more information about this problem. Find me some relevant formulas etc.
 
either that, or the answer is trivial... ;>

I.e., the new de Broglie wavelength would also be 0.00m

...unfortunately, in this case, I don't think you would be justified in ignoring relativistic effects since the momentum is infinite...
 

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