The de Broglie wavelength is simply the wavelength of a particle, but it happens to be immeasurable aside from when applied to elementary particles. A nice problem that demonstrates this:
Giancoli said:
Bullets of mass 3.0g are fired in parallel paths with speeds of 220m/s through a hole of 3.0mm in diameter. How far from the hole must you be to detect a 1.0-cm-diameter spread in the beam of the bullets?
This problem implies that particles can, in fact, possesses the traits of waves, which in this case, is diffraction.
You obviously don't have to attempt this problem, but it does a great job of showing that de Broglie wavelengths are often undetectable, because the answer to this ends up being something around ##1.5*10^{28}\mathrm m##. If someone has created equipment that can adequately follow these bullets, and measure their effects,
well past Proxima Centauri (the closest star to our solar system), then I sure haven't heard of it.
Regarding your last question; ##E=hf## only applies to photons, so it doesn't make any sense to apply it to, say, a human being, which is where I think your confusion is coming from. If you're wanting to find the energy of a human, and have the momentum (with ##p=mv##), it makes much more sense to find the kinetic energy through ##KE={\frac{1}{2}}mv^2##.
I hope this helps
