- #1
lampshade
- 17
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Homework Statement
Show that the de Broglie wavelength of an electron of kinetic energy E (eV) is
[tex]\lambda = \frac{12.3*10^{-8}}{E^{1/2}}[/tex]
Homework Equations
[tex]\lambda = \frac{h}{p}[/tex]
[tex]E = \frac{p^2}{2m}[/tex]
The Attempt at a Solution
I've played around with substituting and things like that, but I can't seem to find that 12.3 number anywhere. I feel like I must be missing something simple, but I'm not sure what.