Deal or No Deal - Odds of a better deal and most likely deal?

  • Thread starter Thread starter moonman239
  • Start date Start date
Click For Summary
SUMMARY

The discussion centers on the game "Deal or No Deal," specifically analyzing the odds of receiving a better offer based on the average value of remaining cases. With five cases left valued at $.01, $5, $10, $50,000, and $100,000, the average offer is calculated at $12,003.002. The odds of getting a better offer in the next round, where four cases must be chosen, are determined to be 50-50 based on the expectation of earnings. The conversation emphasizes the importance of personal financial goals over statistical averages when making decisions in the game.

PREREQUISITES
  • Understanding of basic probability concepts
  • Familiarity with the game mechanics of "Deal or No Deal"
  • Knowledge of statistical averages and expectations
  • Ability to analyze decision-making based on personal financial goals
NEXT STEPS
  • Research the mathematical principles of expected value in probability theory
  • Explore advanced strategies for decision-making in games of chance
  • Learn about risk assessment and personal finance in gambling scenarios
  • Investigate the psychological aspects of gambling and player behavior
USEFUL FOR

This discussion is beneficial for game theorists, gamblers, financial strategists, and anyone interested in the mathematical analysis of risk and reward in decision-making scenarios.

moonman239
Messages
276
Reaction score
0
Deal or No Deal -- Odds of a better deal and most likely deal?

Homework Statement


Suppose I am playing "Deal or No Deal." Assume that the banker's offers always equal the average value of the remaining cases. I have 5 cases remaining. The values of the cases are as follows:

$.01
$5
$10
$50,000
$100,000

thus resulting in an average of $12,003.002. If played another round, I'd have to choose 4 cases. What are the odds of getting a better offer on the next round? What offer would I be most likely to receive?

2. The attempt at a solution

First, I would figure out how many cases had values that were below the median (which is $50, in this case). Call that number x. Then the odds of a better deal on the next round equals x / n! * 4, where n is the number of remaining cases.

As for my other question, I don't know the answer.
 
Physics news on Phys.org


moonman239 said:

Homework Statement


Suppose I am playing "Deal or No Deal." Assume that the banker's offers always equal the average value of the remaining cases. I have 5 cases remaining. The values of the cases are as follows:

$.01
$5
$10
$50,000
$100,000

thus resulting in an average of $12,003.002. If played another round, I'd have to choose 4 cases. What are the odds of getting a better offer on the next round? What offer would I be most likely to receive?

2. The attempt at a solution

First, I would figure out how many cases had values that were below the median (which is $50, in this case). Call that number x. Then the odds of a better deal on the next round equals x / n! * 4, where n is the number of remaining cases.

As for my other question, I don't know the answer.

Well, the average is also the expectation.
That means that if you play a zillion games, you will on average earn $12,003.002.
In other words, to optimize your earnings it doesn't matter what you do.

What are the odds to receive a better offer?
Well, that would be 50-50, because that is what an expectation means.

If you want to play an interesting game, you shouldn't worry about your expected earnings.
You should worry about what you want to earn.

So if you would need for instance $20,000 to buy a house, you can play for that.
You wouldn't care whether you would $5 or $10 or zip, because those are all equally worthless.
And also, you wouldn't accept the offer, because it simply isn't enough to buy your house.
So you'd bet on the less good chance to earn what you really want.

If, after the first round one of the worthless prices is taken away, you'll get an offer of about $38,000 and you should take that right away, because it pays for your house!

You shouldn't go for the $100,000, because you don't need it to pay for your house.

Concluding, I'd say that you would assign different values to the prices than the actual monetary value, because of what you can or cannot do with it.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
5K
Replies
81
Views
12K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 29 ·
Replies
29
Views
7K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
29
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 11 ·
Replies
11
Views
4K