DeBroglie Wavelength Comparison

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Homework Statement


Compare the deBroglie wavelength for an electron in the n=6 orbit of He+ compared to the n=2 orbit. Is the deBroglie wavelength the same, smaller, or larger? Derive this.

Homework Equations



Quantization of Paths of Electrons:
2 pi r = n (lambda)

Bohr Radius:
rn=n2 aB

The Attempt at a Solution



So plugging eqn 2 into eqn 1 and solving for lambda (and using Z = 2 for He+) gives:
wavelength = pi n aB

So using this, the deBroglie wavelength of n=6 would be 3 times larger than the n=2 wavelength?
I really don't know if this is correct. I don't know if the Bohr model can be used with deBroglie (they are kind of related right?)

Edit:
Ok the math symbol stuff is kind of messed up, I fixed what I could but it kept showing things wrong.
 
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