Deceleration necessary to prevent a train collision

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SUMMARY

The discussion centers on calculating the necessary deceleration of a passenger train to avoid colliding with a freight train ahead. The key equations involved are D = vP - 0.5at² for the passenger train and x(t) = vFt for the freight train. The participant attempted to substitute t = (vP - vF)/a into the passenger train's equation but was informed this approach was incorrect. The correct method requires a clear understanding of relative motion and the conditions under which the two trains can avoid collision.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of relative velocity concepts
  • Familiarity with the principles of constant acceleration
  • Basic algebra for solving equations
NEXT STEPS
  • Study the derivation of kinematic equations for constant acceleration
  • Learn about relative motion in physics
  • Explore examples of collision avoidance in train dynamics
  • Investigate the impact of varying deceleration rates on stopping distances
USEFUL FOR

Physics students, train safety engineers, and anyone interested in the dynamics of motion and collision avoidance in transportation systems.

rezal
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Homework Statement


The engineer of a passenger train traveling at vP sights a freight train whose caboose is distance D ahead on the same track. The freight train is traveling at vF in the same direction as the passenger train. The engineer of the passenger train immediately applies the brakes, causing a constant deceleration of a, while the freight train continues with constant speed.
For what range of decelerations a will the train collision be avoided?
Givens: vP,vF,D,

Homework Equations


Passenger Train: D=vP-.5at^2
Freight Train: x(t)=vFt
vP=vF+at

The Attempt at a Solution


I [/B]planned on solving this by substituting
t=(vP-vF)/a
into the equation for the passenger train
D= vP((vP-vF)/a) - .5a((vP-vF)/a)^2
and then solving for a but I was told that this is incorrect?
 
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rezal said:

Homework Statement


The engineer of a passenger train traveling at vP sights a freight train whose caboose is distance D ahead on the same track. The freight train is traveling at vF in the same direction as the passenger train. The engineer of the passenger train immediately applies the brakes, causing a constant deceleration of a, while the freight train continues with constant speed.
For what range of decelerations a will the train collision be avoided?
Givens: vP,vF,D,

Homework Equations


Passenger Train: D=vP-.5at^2
Freight Train: x(t)=vFt
vP=vF+at

The Attempt at a Solution


I [/B]planned on solving this by substituting
t=(vP-vF)/a
into the equation for the passenger train
D= vP((vP-vF)/a) - .5a((vP-vF)/a)^2
and then solving for a but I was told that this is incorrect?
It is incorrect, but who told you that, and did they give you a reason?
 
My TA did but he didn't really give any particular reason as to why.
 

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