The decomposition potential is always higher than the theoretically determined potential by thermodynamics. E=η+Eeq where E is the decomposition potential, η is the overpotential and Eeq is the theoretically determined potential.(adsbygoogle = window.adsbygoogle || []).push({});

And ΔG=-nFE and if we were to substitute the decomposition potential into this equation, the higher the decomposition potential the more negative the Gibbs Free Energy. This seems wrong because intuitively I feel like the higher the decomposition potential the more energy is required. Like in any electrical appliance the greater the voltage the more energy is needed. So what is wrong with my concept here?

**Physics Forums - The Fusion of Science and Community**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Decomposition potential and Gibbs Free Energy

Loading...

Similar Threads - Decomposition potential Gibbs | Date |
---|---|

Potential energy and internuclear distance | Feb 10, 2018 |

Full thermal decomposition of metal oxides? | May 14, 2017 |

Relation between Decomposition and Reversible reactions... | Apr 20, 2017 |

Fe2O3 Thermal Decomposition Question | Jan 12, 2017 |

Sodium Bicarbonate Thermal Decomposition | Jan 31, 2016 |

**Physics Forums - The Fusion of Science and Community**