Decompossing a polynomial (keep getting the wrong result )

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SUMMARY

The discussion focuses on decomposing the polynomial f(x) = -x² - x + 1 into linear terms. The correct factorization involves identifying the roots, which are calculated as \(\frac{-1 \pm \sqrt{5}}{2}\). The proper decomposition is expressed as f(x) = -\left[x - \left(\frac{-1 + \sqrt{5}}{2}\right)\right]\left[x - \left(\frac{-1 - \sqrt{5}}{2}\right)\right]. The participant initially misidentified the factors but corrected the oversight regarding the negative sign.

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decompossing a polynomial (keep getting the wrong result :()

Homework Statement



Given the polynomial f(x) = -x^2 - x + 1, decompose the polynomial into linear terms


The Attempt at a Solution



I get [tex](x-(-(\frac{-\sqrt{5}+1}{2}))((x-(-\frac{-\sqrt{5}-1}{2}))[/tex]

I seem to be missing a integer factor but can't get it to fit properly. Maybe one of you guys can point out my error ? Or where I doing this wrong :)
 
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Well, the roots of your polynomial are [tex]\frac{-1\pm\sqrt{5}}{2}[/tex], so shouldn't you have

[tex]f(x)=-\left[x-\left(\frac{-1+\sqrt{5}}{2}\right)\right]\left[x-\left(\frac{-1-\sqrt{5}}{2}\right)\right][/tex]

?
 


gabbagabbahey said:
Well, the roots of your polynomial are [tex]\frac{-1\pm\sqrt{5}}{2}[/tex], so shouldn't you have

[tex]f(x)=-\left[x-\left(\frac{-1+\sqrt{5}}{2}\right)\right]\left[x-\left(\frac{-1-\sqrt{5}}{2}\right)\right][/tex]

?


forgot the minus 1 I can see. Must be tired. Thanks :)
 

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