- #1
liagee
- 5
- 0
A ball is thrown horizontally from the top of
a building 53.8 m high. The ball strikes the
ground at a point 119 m from the base of the
building.
The acceleration of gravity is 9.8 m/s. The time (I got this answer and it's correct and all) is 3.3135sec.
(part 2 of 4) Find the initial velocity of the ball.
(part 3 of 4) Find the x component of its velocity just before it strikes the ground.
007 (part 4 of 4) 10.0 points
Find the y component of its velocity just before it strikes the ground.vaverage = d/t
a = Vdelta/t
vf = vi + at
I don't even know any others -_-
I tried to use vf^2 = vi^2 + 2ad?? It didn't work. I am really lost but if someone could tell me which formula (kinematics) to use that would be great.I already got the time (part 1 of 4) to equal 3.3135sec but despite using the right equations etc I can't get the other three parts.
a building 53.8 m high. The ball strikes the
ground at a point 119 m from the base of the
building.
The acceleration of gravity is 9.8 m/s. The time (I got this answer and it's correct and all) is 3.3135sec.
(part 2 of 4) Find the initial velocity of the ball.
(part 3 of 4) Find the x component of its velocity just before it strikes the ground.
007 (part 4 of 4) 10.0 points
Find the y component of its velocity just before it strikes the ground.vaverage = d/t
a = Vdelta/t
vf = vi + at
I don't even know any others -_-
I tried to use vf^2 = vi^2 + 2ad?? It didn't work. I am really lost but if someone could tell me which formula (kinematics) to use that would be great.I already got the time (part 1 of 4) to equal 3.3135sec but despite using the right equations etc I can't get the other three parts.
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