Define Organic Compounds As Polar Or Nonpolar

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SUMMARY

The discussion focuses on the polarity of various organic compounds, specifically identifying nonpolar and polar compounds among a list. Participants concluded that decene, decanal, and 3-methyl-2-decene are nonpolar, while 2-butyne, propanal, propanamide, and 3-aminopentane are polar. The consensus indicates that cyclohexanol is polar due to its hydroxyl group, despite its low solubility in water. The final answers for the questions posed are 1.D and 2.E, confirming the polarity classifications of the compounds discussed.

PREREQUISITES
  • Understanding of organic chemistry concepts, specifically functional groups.
  • Knowledge of polarity and its determinants in organic compounds.
  • Familiarity with hydrocarbon structures and their properties.
  • Basic comprehension of alcohols and carbonyl compounds.
NEXT STEPS
  • Study the properties of functional groups in organic compounds.
  • Learn about the polarity of different organic molecules, focusing on carbonyl and alcohol groups.
  • Research the solubility of organic compounds in water and its relation to polarity.
  • Explore the concept of dipole moments and their role in determining molecular polarity.
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Chemistry students, organic chemists, and anyone interested in understanding the polarity of organic compounds and their implications in chemical behavior.

fishes
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1.Which of the following compounds are nonpolar?

1) decene

2) decanal

3) 3-methyl-2-decene

4) 1,2-pentanediol

5) cyclohexanol

Select one:
a. 1,2 and 3 only
b. 1 and 2 only
c. 3,4 and 5 only
d. 1,2,3 and 5 only
e. 1 and 3 only

2. Which of the following compounds are polar?

1) 2-butyne

2) propanal

3) propanamide

4) 3-aminopentane

5) 3-heptene

Select one:
a. 2, 3 and 5 only
b. 1, 3 and 5 only
c. 3,4 and 5 only
d. 1,2,4 and 5 only
e. 2, 3 and 4 only

The Attempt at a Solution


[/B]
1. For this question I'm tossing up between a and d. I'm pretty confident on 1, 2 and 3 because they are hydrocarbons without any functional groups that can donate protons. I know cyclohexanol has a OH functional group which is very polar but the fact that it's not soluble in water is throwing me off. I would probably go with A at the moment.

2. For this one I'm going with E as 5 is an alkene without any functional groups which means it is nonpolar. This cancels out A-D.

Thanks for the help!
 
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fishes said:
I'm pretty confident on 1, 2 and 3 because they are hydrocarbons without any functional groups that can donate protons

You don't need a group donating protons for molecule to be polar. Chloromethane is polar.
 
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Borek said:
You don't need a group donating protons for molecule to be polar. Chloromethane is polar.
Good to know! I don't think that changes any of my answers though so were they right?
 
fishes said:
I don't think that changes any of my answers

It does ;)

Analyze the first question again.
 
Does that mean cyclohexanol isn't polar so the answer would be 1.D and 2.E ? Thanks for all the help by the way!
 
No, cyclohexanol is polar (all alcohols are, just like products of their oxidation).
 
Well if A and D are wrong for 1 I assume it's between B and E? In that case I would go with E as aldehydes are a lot more polar than alkenes?
 
E would be my answer.
 
Sounds good but I thought that aldehydes were considered to be pretty nonpolar which would mean decanal would be nonpolar as well as its the simplest 10 carbon aldehyde?
 
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They are definitely more polar than hydrocarbons. Carbonyl itself is quite polar.
 
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