Define Organic Compounds As Polar Or Nonpolar

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Discussion Overview

The discussion revolves around the classification of various organic compounds as polar or nonpolar, focusing on specific examples such as decene, decanal, and cyclohexanol. Participants explore the criteria for determining polarity, including the presence of functional groups and molecular structure.

Discussion Character

  • Debate/contested
  • Conceptual clarification
  • Mathematical reasoning

Main Points Raised

  • Some participants suggest that decene, decanal, and 3-methyl-2-decene are nonpolar due to their hydrocarbon nature and lack of functional groups that can donate protons.
  • Others argue that cyclohexanol is polar because it contains an -OH functional group, although its solubility in water raises questions.
  • One participant asserts that a molecule does not need a proton-donating group to be polar, citing chloromethane as an example.
  • There is a discussion about the polarity of aldehydes, with some participants suggesting that they are more polar than alkenes, while another expresses uncertainty about the polarity of decanal.
  • Participants express varying levels of confidence in their answers to the questions posed, with some reconsidering their choices based on the polarity of functional groups.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the classification of the compounds as polar or nonpolar, with multiple competing views and ongoing debate regarding the criteria for polarity.

Contextual Notes

Some statements reflect uncertainty about the polarity of specific compounds, and there are unresolved assumptions regarding the influence of functional groups on molecular polarity.

fishes
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1.Which of the following compounds are nonpolar?

1) decene

2) decanal

3) 3-methyl-2-decene

4) 1,2-pentanediol

5) cyclohexanol

Select one:
a. 1,2 and 3 only
b. 1 and 2 only
c. 3,4 and 5 only
d. 1,2,3 and 5 only
e. 1 and 3 only

2. Which of the following compounds are polar?

1) 2-butyne

2) propanal

3) propanamide

4) 3-aminopentane

5) 3-heptene

Select one:
a. 2, 3 and 5 only
b. 1, 3 and 5 only
c. 3,4 and 5 only
d. 1,2,4 and 5 only
e. 2, 3 and 4 only

The Attempt at a Solution


[/B]
1. For this question I'm tossing up between a and d. I'm pretty confident on 1, 2 and 3 because they are hydrocarbons without any functional groups that can donate protons. I know cyclohexanol has a OH functional group which is very polar but the fact that it's not soluble in water is throwing me off. I would probably go with A at the moment.

2. For this one I'm going with E as 5 is an alkene without any functional groups which means it is nonpolar. This cancels out A-D.

Thanks for the help!
 
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fishes said:
I'm pretty confident on 1, 2 and 3 because they are hydrocarbons without any functional groups that can donate protons

You don't need a group donating protons for molecule to be polar. Chloromethane is polar.
 
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Borek said:
You don't need a group donating protons for molecule to be polar. Chloromethane is polar.
Good to know! I don't think that changes any of my answers though so were they right?
 
fishes said:
I don't think that changes any of my answers

It does ;)

Analyze the first question again.
 
Does that mean cyclohexanol isn't polar so the answer would be 1.D and 2.E ? Thanks for all the help by the way!
 
No, cyclohexanol is polar (all alcohols are, just like products of their oxidation).
 
Well if A and D are wrong for 1 I assume it's between B and E? In that case I would go with E as aldehydes are a lot more polar than alkenes?
 
E would be my answer.
 
Sounds good but I thought that aldehydes were considered to be pretty nonpolar which would mean decanal would be nonpolar as well as its the simplest 10 carbon aldehyde?
 
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They are definitely more polar than hydrocarbons. Carbonyl itself is quite polar.
 
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