Defining of function in equation

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SUMMARY

The discussion centers on the function definition in the equation \varphi(x)=f(x)+\int^{b}_{a}K(x,y)\varphi(y)dt, where f is a continuous function on the interval [a,b] and K is a continuous function on the Cartesian product [a,b]×[a,b]. Participants clarify that while C([a,b]) denotes continuous functions, it does not imply differentiability, which is instead represented by C1([a,b]). The Cartesian product [a,b]×[a,b] is confirmed as the correct terminology for constructing ℝ² space.

PREREQUISITES
  • Understanding of continuous functions, specifically C([a,b])
  • Knowledge of differentiable functions, specifically C1([a,b])
  • Familiarity with integral equations and their components
  • Basic concepts of Cartesian products in set theory
NEXT STEPS
  • Study the properties of continuous functions in C([a,b])
  • Explore the implications of differentiability in C1([a,b])
  • Learn about integral equations and their applications
  • Investigate Cartesian products and their role in higher-dimensional spaces
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Mathematicians, students studying calculus or real analysis, and anyone interested in the properties of continuous and differentiable functions.

matematikuvol
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[tex]\varphi(x)=f(x)+\int^{b}_{a}K(x,y)\varphi(y)dt[/tex]

[tex]f:[a.b]→ℝ[/tex]
[tex]K(x,y)→[a,b]\times [a,b]→ℝ[/tex]

Is [tex][a,b]\times [a,b][/tex] Deckart product? Is that the way to construct [tex]ℝ^2[/tex] space?

If I say [tex]f\in C([a,b])[/tex], [tex]K\in C([a,b]\times [a,b])[/tex] that means that [tex]f[/tex] and [tex]K[/tex] are differentiable on this intervals. Right?
 
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Yes, [itex][a, b]\times [a, b][/itex] is the "Cartesian product" (named for DesCartes so what you mean by "Dekart product"), the set of all ordered pairs of numbers from the interval [a, b].

However, C([a, b]) is NOT the set of differentiable functions. It means simply functions that are continuous on [a, b], not necessarily differentiable. C1([a, b]) is the set of functions that are at least once differentiable on [a, b].
 
Tnx for the answer.
 

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