Why are complex numbers represented on a plane?

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SUMMARY

The discussion centers on the representation of complex numbers in the complex plane, specifically the notation ##z = x + iy## and its equivalence to coordinates in ##\mathbb{R}^2##. Participants emphasize the significance of defining a complex plane due to unique properties of complex multiplication, such as rotation by the argument of a complex number. Key insights include the existence of multiplicative inverses and n-th roots for nonzero complex numbers, as well as the implications of complex derivatives and Taylor series within a disk.

PREREQUISITES
  • Understanding of complex numbers and their notation (e.g., ##z = x + iy##).
  • Familiarity with the concept of the complex plane and its geometric representation.
  • Basic knowledge of complex multiplication and its properties.
  • Introduction to complex analysis, particularly complex derivatives and Taylor series.
NEXT STEPS
  • Study the properties of complex multiplication and its geometric interpretations.
  • Learn about the significance of complex derivatives and their applications in complex analysis.
  • Explore the concept of Taylor series in the context of complex functions.
  • Investigate the implications of line integrals in complex analysis, including Cauchy's integral theorem.
USEFUL FOR

Students and professionals in mathematics, particularly those studying complex analysis, as well as educators seeking to clarify the differences between complex numbers and vectors in ##\mathbb{R}^2##.

Destroxia
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So I know that a complex number can be represented by ##z=x+iy##, where ## z = x + iy \in \mathbb{C}##.

Would it be okay to then state that ## z = x + iy \in \mathbb{C} := (x,y) \in \mathbb{R}^2 ##?

If we can just look at complex numbers as coordinates in ##\mathbb{R}^2## what is the point of even defining a complex plane? (just started learning these math logic notations, so pardon me if my intuition is incorrect)
 
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RyanTAsher said:
If we can just look at complex numbers as coordinates in R2\mathbb{R}^2 what is the point of even defining a complex plane?
multiplication
 
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And mapping a function f(z) = w onto a companion complex plane which consists of the points w = u + i v
 
wrobel said:
multiplication

Okay, but couldn't you just use properties of vectors in ##\mathbb{R}^2##, and treat each point as a position vector?
 
RyanTAsher said:
Okay, but couldn't you just use properties of vectors in ##\mathbb{R}^2##, and treat each point as a position vector?
It's a lot less abstract with a simple graphical representation.

Also, it makes finding all the roots of zn + k = 0 a snap.
 
SteamKing said:
And mapping a function f(z) = w onto a companion complex plane which consists of the points w = u + i v

So there would be no way to map a ##\mathbb{R}^2## vector function onto another companion plane of ##\mathbb{R}^2## ? I feel like I'm not understanding something...
 
RyanTAsher said:
So there would be no way to map a ##\mathbb{R}^2## vector function onto another companion plane of ##\mathbb{R}^2## ? I feel like I'm not understanding something...
Look, these are ways of simplifying things. Why do you want to make stuff harder than it should be?

We could replace plane geometry with analytic geometry and make the former 10 times harder than it already is. What would be the point?
 
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The most important difference between C and R2 is the way multiplication is defined. For any complex number, z, multiplying other numbers by z will rotate them by the argument of z. Vectors in R2 don't have anything simple like that. Making a connection between the fundamental geometric property of rotations and the fundamental algebraic property of multiplication has profound consequences. For instance:
1) Every nonzero complex number z has a multiplicative inverse. (Just like every rotation has a rotation in the opposite direction. Likewise for the scaling.)
2) Every nonzero complex number z has an n'th root. (Just like every rotation can be done in n smaller rotations. Likewise for the scaling.)
3) The complex derivative of a complex values function, f, can be defined mimicking derivatives of real functions. The existence of a complex derivative in a disk has surprising consequences:
a) All higher order derivatives exist in the disk.
b) The Taylor series converges in the disk and represents the function.
c) The value of line integrals within the disk have simple values. Loop integrals are 0. Other line integrals from a to b are independent of the line path between a and b.
d) Maximums and minimums of the real and imaginary parts of f occur on the circumference of the disk.
e) The values of the function inside the disk is completely determined by its values on the circumference of the disk.
 
SteamKing said:
Look, these are ways of simplifying things. Why do you want to make stuff harder than it should be?

We could replace plane geometry with analytic geometry and make the former 10 times harder than it already is. What would be the point?

I just didn't really see the difference, because I've just started complex analysis, they seemed like the same process to me, not one was more simple than the other. I think I understand a bit now.

FactChecker said:
The most important difference between C and R2 is the way multiplication is defined. For any complex number, z, multiplying other numbers by z will rotate them by the argument of z. Vectors in R2 don't have anything simple like that. Making a connection between the fundamental geometric property of rotations and the fundamental algebraic property of multiplication has profound consequences. For instance:
1) Every nonzero complex number z has a multiplicative inverse. (Just like every rotation has a rotation in the opposite direction. Likewise for the scaling.)
2) Every nonzero complex number z has an n'th root. (Just like every rotation can be done in n smaller rotations. Likewise for the scaling.)
3) The complex derivative of a complex values function, f, can be defined mimicking derivatives of real functions. The existence of a complex derivative in a disk has surprising consequences:
a) All higher order derivatives exist in the disk.
b) The Taylor series converges in the disk and represents the function.
c) The value of line integrals within the disk have simple values. Loop integrals are 0. Other line integrals from a to b are independent of the line path between a and b.
d) Maximums and minimums of the real and imaginary parts of f occur on the circumference of the disk.
e) The values of the function inside the disk is completely determined by its values on the circumference of the disk.

Thank you for this list, the concept of the rotation of values makes the difference a lot more clear to me, also the part on line integrals.
 

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